Question

Combining 0.350 mol Fe, O, with excess carbon produced 13.7 g Fe. Fe,O, +3C- 2 Fe + 3 CO What is the actual yield of iron in moles? actual yield: ou What is the theoretical yield of iron in moles? theoretical yield: mol What is the percent yield? percent yield:

Answer 1

Fez O3 +30 - 2Fe + 300 balanced equation. combining 0:350 mol fego z with excens carbon prodeeced 13.7 g fe Molar mass of fe = 55.8 gm/mol Now Bizg of reo Argo gn of & = 55.8 qmimoi team of Fe = 0.245 mol of Fe Now I mol of Fe2O3 produced 2 o mol of Fe 0.350 Ⓡutes mol of F202 2rmol of Fe X 0.350 met of Fe2O3 Įmolof Fe2O3 =) Or7 mol of Fe Actual yield = 0.245 mol of Fe theoritical yield = o.f mol of te Now we know that percent yield= Actual Yield the critical Yield X100 , ^ 0.245 -XIOO Y 0.7 = 35 y . Actual yield = 1 of iron 0.295 mol 0.7 mol .. theoritical Yield = of iron Ja percent yield = 357. )