Question

Combining 0.359 mol Fe, O, with excess carbon produced 14.7 g Fe. Fe, O3C-2 Fe +3 CO What is the actual yield of iron in moles? actual yield: What is the theoretical yield of iron in moles? theoretical yield: What is the percent yield?

Answer 1

& Solution Fe₂O₃ + 3C - 25e +300: In 14.7 As per question, 0.359 mot of fe eos with excess carbon produced 14.7g offe Has of iom formed = 14.7g No of moles of ison formed = bere Mass ofirun Molar ofan of cron - 14.7g 56g No of miles of is (82625 moles] [Molar mas of 2. Actual yield of iron = [ 0.2625 moles] As per question, it is already mentioned that carbon is in excess so here Fees is the dimiting reagent According to equation, FeO, + 3 C afe+3co

As FO is the limiting reagent, so product formation would be governed by amount of feads taken As per equation Imole of Fee Oz gosas gives 2 motes offe s 160g gives 2x 56g of fe 2x56 Qol Fe 160 and 0.359x160g 28 56 X0-359x160 g 160 0.959 note offers gives uogoffe & Theoretical field - 40g] of im Giren Mans offers = ro of moles y Molar mas = 0.3598160g & op yield - Actuel yeld x 100 p Theoretical yield = 14.72 x 100 %. = 36.75.1.1 ५०१