On a hot day, the temperature of a 33,000 L swimming pool increases by 1.70°C. What is the net heat transfer (in J) during this heating? Ignore any complications, such as loss of water by evaporation. (Enter the magnitude.)
mass of water, m = volume * density
m = 33000* 10^-3* 1000
m = 33000 kg
heat need to be transfered
H = m C ( dT)
H= 33000* 4186* 1.7
H = 2.348*10^8 J
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