Question

A swimming pool (dimensions: 50m x 2m50 x 16m) has a temperature of 20.00°C. Due to the evaporation of the surface water, this pool loses approximately 910.0 kJ/m2.h. To compensate for this loss, the water is heated by burning methane (CH4). Methane has a pressure of exactly 4 atm and a temperature of 20.00°C. What volume of methane should be burned?

Answer [4911 l/h]

Answer 1

Solution : Heat of combustion of Methane can be obtained from perry's chemical engineering handbook or NIST web book as well and it is equal to -890.7 kj/mol where negative sign depicts exothermic reaction
Solution 1 web -CAuig + 2020 CO2 + 2H20 19) NIST quem Persona o Clemical Engineering terms book (M) com bastion kg ( wiele op Motiane Ploss = 1 910 kj/m2. h 890.7 TOTO pool som - 2.591 Given To Zooc , rate of Hear los = 900 kg / m² h Swu Suҷаи очо 4 hos Кьојки fout out Hotel Z16X50 - Soom? This Overall care of tear lors - Glass X 800 m² = 910x 800 = 728 ooo kylt aurel Sluce lude Burning a Methane releases 802.3 kJ Thus, No. of Moves of Methane Chy required = 428000 / Part 890.7 = admoes of Cthy per hour 817. 334 S ith

and sluce Guven C B= Yatm Tano 20°C = 273,15+20k= 293.15 and Moles required femaludes/ R K 817.734 a This possuming Methone to be dead Gas a PV & ART When R=0.0821 liter atm Indok (817.334) 4X V- ARROGRX' : 0821x29315 (817.334) Ve Ben x 0,0821 x 293-15 !!! r = 4S ABEBD Modelle 4917.8241 elke 1. Thus Volumetric flow rate of Methane should be Va 4914.8241 eft appeak.