Question

To understand how to apply the equations for one-dimensional motion to the x and y directions separately in order to derive standard formulas for the range and height of a projectile. (Figure 1) A projectile is fired from ground level at time t=0, at an angle with respect to the horizontal. It has an initial speed vo. In this problem we are assuming that the ground is level. 

Part A Find the time tH it takes the projectile to reach its maximum height H. 

Part B Find tr, the time at which the projectile hits the ground after having traveled through a horizontal distance R. 

Part D Find the total distance R (often called the range) traveled in the x direction; see the figure in the problem introduction. 

Answer 1

3 L * Vocoso V 40 Jay=-g I Vosinol V loso R- - (A) in y direction Vy-uă = 2gs | At Heighest pont " لا يه كه منع ) -2م Vy = Uy tayt o= (No sino - gt . . » += Vo sino Sof byt + £ ayt? I vertical Component of o= sinot - Ž gt² displacement o=+ { vo sino - Ž gt? » Ž gt = vo sino 2 = 2, 1ms > tag D) R=(%o cose)xt =(vo.coso)(avo sin o) g = Vo? (asino6050)Va sinzo

In part (D) calculation has been done in x direction . X component of velocity is constant during the whole projectile motion.