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Block A (0.40 kg) and block B (0.5 kg) are on a frictionless table (see figure). Spring 1 connects block A to a frictionless

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Answer #1

For bloc k B sm VE 0.5 (2) (0.6t0.4) kx 0.061 Awnver N/M k = 32.8 1

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Answer #2

(.5*2^2)/(.6+.4)*0.61) = K 


Algebraically: K = (m*v^2)/(r1+r2)*△x


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answered by: Joe
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