Question

Qs8. Complete all four reactions. Explain the differences, if any. Consult Ch 23-7. OH RCVAICI RCI/AICI: HCl dilute NHCH3 Bry/AIBr; Brz/AIBr; HCl dilute

Answer 1

1. Since the reactions given above is an example of the electrophilic aromatic substitution reaction, the given reactants are PHENOL and N-METHYL ANILINE, here the groups present are Electron donating group (+M) which favours the attack of the electrophile on the benzene at ORTHO and PARA positions.

2. The products of the reactions is given below
OH OH 애 Red/Alcly dil Hel + e meta prodnut ortho prodret para product Ave HN H elly Bral Albiz Bora / Al dil Hd Br. meta procact. O, W-methyl- - Amiline Ortho produt Br Para product

3. But in the presence of the acid the +M effect of the -OH and -NHMe group changes to the (-M) effect which favours the attack of the electrophile at META positions,
In presence of Acid, the th effect of the -oh s HN CH3 group changes to the |-M ethect, so, the yield is the meta substituted poroduet. HLOHcio " HH b 'm effect" which directs the electrophile towards the meta position" + M effect " which directs the electrophile tonends Ortho Spara positions" similarly for; 1 -1 +m effect ethest