a)4. In the given table we have the data of type I error and type II error, now in the following table we have to calculate the expected cost and we have also given type I error cost 20 and type II error cost 4.
s= | 0.0 | 0.1 | 0.2 | 0.3 | 0.4 | 0.5 | 0.6 | 0.7 | 0.8 | 0.9 | 1 | |
Type I expected cost | 0.2*20=4 | 0.18*20=3.6 | 0.16*20=3.2 | 0.14*20=2.8 | 0.12*20=2.4 | 0.1*20=2 | 0.08*20=1.6 | 0.06*20=1.6 | 0.04*20=0.8 | 0.02*20=0.4 | 0.00*20=0 | |
Type II expected cost | 0.2*4=0.8 | 0.21*4=0.84 | 0.22*4=0.88 | 0.23*4=0.92 | 0.24*4=0.96 | 0.24*4=0.96 | 0.29*4=1.16 | 0.36*4=1.44 | 0.36*4=1.44 | 0.45*4=1.80 | 0.5*4=2 | |
Total expected cost | 4+0.8=4.8 | 3.6+0.84=4.44 | 3.22+0.88=4.08 | 2.8+0.92=3.72 | 2.4+0.96=3.36 | 2+0.96=2.96 | 1.6+1.16=2.76 | 1.6+1.44=3.04 | 0.8+1.44=2.24 | 0.4+1.80=2.20 | 0+2=2 |
So the stricnesss of standard proof is the probability of type II error with 0.5 i.e when a guilty person is found to be innocent with probability 0.5. It means guilty person is innocent with probability half.
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