Question

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1. Look up succinic acid in the Merck Index (hard-copy from Library reserve) or in a MSDS (Material Safety Data Sheet from many Internet sources). a) What is its molecular formula? b) What is its molar mass? c) Describe its hazard properties in a few words. 2. Use equations from the Calculations page for the following: If you use 13.024 g of a 5.00% succinic acid solution in this experiment, a) how many grams of succinic acid will be present (show work)? b) How many moles of succinic acid will be present (show work)? 3. The following chemical reaction is balanced: CaCO3+2 HCI CO2 +H2O +CaCl2 a) If 2.0 moles of CaCO3 reacted, how many moles of CO2 would form? b) What is the ratio of moles of CaCO3 to moles CO2? (This is the same as the conversion factor from the coefficients,) c) What ratio do you expect for moles of HCl to moles CO2? (This is the same as the conversion factor from the coefficients.) d) If you did an experiment and found (1.98 moles HCl / mole CO2) and the experimental method was sufficient for 2 significant figures, would your experimental ratio agree or disagree with the previous question's answer? Explain briefly. 4. The symbol "M" is an abbreviation for (moles /L). It can be used as a conversion factor. If vou have a solution that is 2.00 M and you use 0.0089 L, how many moles did you use?

Answer 1

(I) (a) Molecular formulae of succinic acid 44604 (6) Molar mass of succinic acid = 4x12 + 6 X1 + 4X16 = 48 +6 +64 = 118 (e) Hazard proper tres are it is corrosive and Irritating. It mistation to skin, mucay membrane and despiratoy tract. It britate eye mostly. 13.024 g of a 5 % succinic acid used then 5% mean 59 in 100 ml Solvent (logo) We use 13.094 g of Solution .It mean Solution of 13.094 g contain = 13-094X5 g And = 0.6512 gm. hora mole = goven masse = 0.6512 = 0.0055 Mole for used schuhen moler mass - 118 (3) CaCO₃ + 2HCl - Cog + HgO + Calla I (9) I mole of CaCO3 give I mole of Cog I mole of " " I mole of coa

(b) i mol Cacoz = 1 mole.com CaCO3 - cog (③ I Ratio of mole > 1:1 g mole g HCl - I mole of cog HOP - g mol cog i mol Ratio g HCP : cog > 2:1 Since I mole of He used for I mole Cog So experiment baho agree with previsus Question By Applying Molandy equestion : mm = mg ra Cold Sch) (Hewe Sol) IXIL = mg x 0.6089 L I (A) х 2 mg = 0-0089 solution = = 224.719 224.719 Mole Mole in new