Question

3. The following chemical reaction is balanced: CaCO3 +2 HCI CO2+H20+CaCl2 a) If 2.0 moles of CaCO3 reacted, how many moles of CO2 would form? b) What is the ratio of moles of CaCO3 to moles CO2? (This is the same as the conversion factor from the coefficients.) c) What ratio do you expect for moles of HCl to moles CO2? (This is the same as the conversion factor from the coefficients.) d) If you did an experiment and found (1.98 moles HCl/mole CO2) and the experimental method was sufficient for 2 significant figures, would your experimental ratio agree or disagree with the previous question's answer? Explain briefly. 4. The symbol "M" is an abbreviation for (moles/L). It can be used as a conversion factor. If you have a solution that is 2.00 M and you use 0.0089 L, how many moles did you use?
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Answer 1

Solution : * 37 CaCO₃ + 2Ha co2+ H2O + Cach a) ff 2 moles of Caloz reacts, then co2 formed will also be 2 moles, as above equation (balanced shows for 1 mole of Calos, 1 mole of coo would form. b) Ratio of medles of CaCO3 to moles of coz is 1:1 i.e. 1. c) Moles of Hel to moles of coz should be 2 or more than 2 for reaction to be corried in forward direction. As 2 moles of Hel is minimum required to produce 1 mole of co2. d) Experimental ratio is 1.98 moles Hel/ mole of ca and as per balanced reaction aboue, minimum 2 moles of He for 1 mole of cone , i.e. 2 medes of na moles of Con, Therefore it totally disagree with the acted calculation. * 47 M= moles / Given, M=2 8 L=0.0089 ; moles=? = moles 2 0.0089 :. moles= Qiaat 10.0178