3)
Given:
m = 150 g
C = 0.44 J/g.oC
Ti = 525 oC
Tf = 100 oC
use:
Q = m*C*(Tf-Ti)
Q = 150.0*0.44*(100.0-525.0)
Q = -28050 J
Negative sign shows that heat has been released.
Answer: 28050 J
4)
Given:
Q = 333 J
m = 50 g
C = 0.5 J/g.oC
use:
Q = m*C*(delta T)
333 = 50.0*0.5*delta T
delta T = 13.32 oC
delta T = 13.32 oC
Answer: 13.3 oC
5)
Given:
Q = -5550 J
C = 0.24 J/g.oC
Ti = 0 oC
Tf = -353 oC
use:
Q = m*C*delta T
-5550 = m*0.24*(-353)
m = 65.5 g
Answer: 65.5 g
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