Question

4. Consider the following standard reduction potentials, Al3 (aq)+3 e Al(s) 12(s)2 e2 1(aq) E = -1.66 V +0.54 V iT E Under standard conditions: A. Al3(aq) is a stronger oxidizing agent than 12(s), and I(aq) is a stronger reducing agent than Al(s). B. 12(s) is a stronger oxidizing agent than Al3*(aq), and Al(s) is a stronger reducing agent than I'(aq). C. Al(s) is a stronger oxidizing agent than I-(aq), and Al3 (aq) is a stronger reducing agent than l2(s). D. I(aq) is a stronger oxidizing agent than Al(s), and I2(s) is a stronger reducing agent than Al3(aq).

Answer 1

G Given that Al3+ (aq) +3é AILS? C'=-1.66 2(6) trt 2 I (aal E = +0.54v. According to Electrochedical series In both half reaction Alt is reduced to Als) while I z is reduced to I but reduction Potential for reduction of Iz to I is positive and that for Al Al is negative. Therefore Iz reduced easily to I than reduction of Aut to al so Incs is better or stronger oxidizing agent than A et (aa). But due to negative reduction potential al oxidizes itself I to A13+ easily than I oxidizes itself to In B coz of Positive reduction potential. Hence, Alls) is stronger ] reducing agent than I (aa). we know that substance which oxidize itself is known as reducing agent and the substance that reduce itself Known as oxidizing agent. so, option - ② I 2 (s) is stronger oxidizing agent than Alst (aa) and Alls) is stronger

reducing agent than I (aa) correct we can also see or locate the position of these tero reduction half reaction on electrochemical serieso In electrochemical series we can also compare the strength of oxidizing or reducing agent.