Given: 2H+(aq)+2e– ⇌H2(g);E°=0.00 Li+(aq)+e– ⇌Li(s);E°=–3.04V F2(g)+2e– ⇌2F–(aq);E°=2.87 Al3+(aq)+3e– ⇌Al(s);E°=–1.66V Pb2+(aq)+2e– ⇌Pb(s);E°=–0.13V Under standard-state conditions, which is...

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Given: 2H+(aq)+2e– ⇌H2(g);E°=0.00 Li+(aq)+e– ⇌Li(s);E°=–3.04V F2(g)+2e– ⇌2F–(aq);E°=2.87 Al3+(aq)+3e– ⇌Al(s);E°=–1.66V Pb2+(aq)+2e– ⇌Pb(s);E°=–0.13V Under standard-state conditions, which is...

Given:

2H+(aq)+2e– ⇌H2(g);E°=0.00

Li+(aq)+e– ⇌Li(s);E°=–3.04V

F2(g)+2e– ⇌2F–(aq);E°=2.87

Al3+(aq)+3e– ⇌Al(s);E°=–1.66V

Pb2+(aq)+2e– ⇌Pb(s);E°=–0.13V

Under standard-state conditions, which is the strongest oxidizing agent? Select one:

a. Pb2+

b. Al3+

c. F2

d. Li+

e.H+

science chemistry

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Answer 1

Answer #1

Ans : C - F2 is the strongest oxidising agent. It is because it is having highest positive Reduction potential . So it has highest tendency to get reduce.

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Answer 2

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Add Answer to: Given: 2H+(aq)+2e– ⇌H2(g);E°=0.00 Li+(aq)+e– ⇌Li(s);E°=–3.04V F2(g)+2e– ⇌2F–(aq);E°=2.87 Al3+(aq)+3e– ⇌Al(s);E°=–1.66V Pb2+(aq)+2e– ⇌Pb(s);E°=–0.13V Under standard-state conditions, which is...

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Add Answer to:
Given: 2H+(aq)+2e– ⇌H2(g);E°=0.00 Li+(aq)+e– ⇌Li(s);E°=–3.04V F2(g)+2e– ⇌2F–(aq);E°=2.87 Al3+(aq)+3e– ⇌Al(s);E°=–1.66V Pb2+(aq)+2e– ⇌Pb(s);E°=–0.13V Under standard-state conditions, which is...