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Thermochemistry
2. Re-arrange as appropriate and combine the first two equations to get the third equation and determine the heat of reaction
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2) N204 (5) → Nat (aa) + A caa) 040 =-44 kJ/mee Reversing this equations Net Coa) + OTA (C) ► N2@14 (8) — 0 040 = +44ky/mol N

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