Combine 2 equations to obtain the third reaction equation
Reaction 1: Solid sodium hydroxide dissolves in water to form an aqueous solution of ions.
NaOH(s) → Na+(aq) + OH–(aq) ΔH1 = ?
Reaction 2: Solid sodium hydroxide reacts with aqueous hydrochloric acid to form water and an aqueous solution of sodium chloride.
NaOH(s) + H+(aq) + Cl–(aq) → H2O(l) + Na+(aq) + Cl–(aq) ΔH2 = ?
Reaction 3: Solutions of aqueous sodium hydroxide and hydrochloric acid react to form water and aqueous sodium chloride.
Na+(aq) + OH–(aq) + H+(aq) + Cl–(aq) → H2O(l) + Na+(aq) + Cl–(aq) ΔH3 = ?
Combine two of the above equations algebraically to obtain the third reaction equation.
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2. Re-arrange as appropriate and combine the first two equations to get the third equation and...
2. Re-arrange as appropriate and combine the first two equations to get the third equation and determine the heat of reaction. Show your workings clearly. (4 pts) NaOH(s) Na+ (aq) + OH-(aq) AH°= -44.0 kJ/mol NaOH(s) + H(aq) + Cl(aq) → H2O(0) + Na*(aq) + Cl(aq) AH--100.1 kJ/mol Na*(aq) + OH (aq) + H*(aq) + Cl'(aq) → H2O(0) + Na+ (aq) + Cl(aq) AH°= ?
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2. Re-arrange as appropriate and combine the first two equations to get the third equation and determine the heat of reaction. Show your workings clearly. (4 pts) NaOH(s) Na+ (aq) + OH-(aq) AH°= -44.0 kJ/mol NaOH(s) + H(aq) + Cl(aq) → H2O(0) + Na*(aq) + Cl(aq) AH--100.1 kJ/mol Na*(aq) + OH (aq) + H*(aq) + Cl'(aq) → H2O(0) + Na+ (aq) + Cl(aq) AH°= ?
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2. Re-arrange as appropriate and combine the first two equations to get the third equation and determine the heat of reaction. Show your workings clearly.(4 pts) AH -44.0 kJ/mol NAOH(s) Na(aq) + OH-(aq) NaOH(s)+ H'(aq) + Cl (aq) H2O() + Na (aq) + Cr(aq) AH=-100.1 kJ/mol H2O()+ Na (aq) + Cl(aq) AH°=? Na (aq)+OH (aq) + H*(aq) + Cl'(aq)
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#3
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