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Multiple Choice (2 pts each) 6: Calculate the pH of a buffer containing 0.010 M lactic acid (pK,-3.86) and 0.050 M sodium lac
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1) Answer C is correct, sinca water is not only in cells for chemical species to move freely, but to allow many of them which are polar to dissolve and react and/or interact.

2) Catabolism involves oxidative reactions that break down molecules, while anabolism involves reductions to build up molecules. The right answer is therefore B.

3) A, B and C are correct, since they all describe activities in which proteins are involved.

4) Enzymes act as catalysts in cells, so their effect is the typical catalyst effect of reducing the energy difference between the substrate and transition state levels (C).

5) A is the right question, since enzymes have very specific pH intervals at which they can function, hence the need of efficient buffering in the cells.

6) We can use the Henderson-Hasselbach equation:

pH = pka + log lactate [lactic] / 0.050M = 3.86 + log(011) = 4.56

7) The amino-acid is not fully protonated. Carboxylate (-COOH) groups are protonated, as is the imino group (C=NH), but the amino groups are not, so this is near neutrality; that is: pH = 6.

8) Each ionizable groups adds a plateau to the two plateaus that are present in all the aminoacid titration curves, so the answer is C: three.

9) The fact that keeps the peptide bond practically planar is the extended pi electron system from the resonance structures, that give the peptide bond a double bond character. D is the right answer.

10) The reason secondary structures occur is because of the hydrogen bonds between the atoms of the peptide bond. Side chains may help or impede the formation of a certain secondary structure, but the basis are the hydrogen bonds mentioned, so A is the right answer.

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