ZuoTi.Pro
Question

46.

CHEMWORK 2+ ion forms complex ions with I as follows: The Hg Hg2IHgI = 1.0 x 108 Кi HgI IHgl2 К2 3D 1.0 х 105 Hgl2 IHgI3 = 1

science   chemistry   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

Answe GiNen information, 46 k2=loxio alu the aboe. for this eguiltbiun Constant, kc = l030 ke is We acsumc hart, 24 All he Ha1 Here is 5-0.16 30 0.04 30 0.04 O.o4 30 x (u-a4 .299% (o33 Concenation Concentation dC .84M Con anbaton : 7299x035

0 0
Add a comment
Know the answer?
Add Answer to:
46. CHEMWORK 2+ ion forms complex ions with I' as follows: The Hg Hg2IHgI = 1.0...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • Lunes CHEMWORK The Hg2+ ion forms complex ions with I as follows: Hg2+ + HgT+ HgI + 1 =Hg2 K1 = 1.0 108 K2=1.0 x 10...

    Lunes CHEMWORK The Hg2+ ion forms complex ions with I as follows: Hg2+ + HgT+ HgI + 1 =Hg2 K1 = 1.0 108 K2=1.0 x 105 K3 -1.0 x 10° K4 = 1.0 * 108 Hgl2 + 1 + HgI3 HgI3 + 1 = Hg142 A solution is prepared by dissolving 0.057 mol Hg(NO3)2 and 5.00 mol Nal in enough water to make 1.0 L of solution. Calculate the equilibrium concentration of [Hg142]. (Hg142) = M Calculate the equilibrium concentration...

  • The Hg2 ion forms complex ions with I' as follows: Hg2 HgI* K1 1.0x 108 HglIHg2...

    The Hg2 ion forms complex ions with I' as follows: Hg2 HgI* K1 1.0x 108 HglIHg2 Ка— 1.0 х 105 Hgl2 IHgl3" K3 1.0 x 109 Hgl3IHgl42K4= 1.0 x 108 A solution is prepared by dissolving 0.044 mol Hg(NO3)2 and 5.00 mol Nal in enough water to make 1.0 L of solution Calculate the equilibrium concentration of [Hgl42 ]. [Hgl 2- Calculate the equilibrium concentration of [I']. [ Calculate the equilibrium concentration of [Hg [Hg2= м

  • The Hg2+ ion forms complex ions with I- as follows: Hg2+ + I- HgI+ K1 =...

    The Hg2+ ion forms complex ions with I- as follows: Hg2+ + I- HgI+ K1 = 1.0 × 108 HgI+ + I- HgI2 K2 = 1.0 × 105 HgI2 + I- HgI3- K3 = 1.0 × 109 HgI3- + I- HgI42- K4 = 1.0 × 108 A solution is prepared by dissolving 0.053 mol Hg(NO3)2 and 5.00 mol NaI in enough water to make 1.0 L of solution. Calculate the equilibrium concentration of [HgI42- ]. [HgI42- ] = M Calculate...

  • The Hg2+ ion forms complex ions with I- as follows: Hg2+ + I- HgI+ K1 =...

    The Hg2+ ion forms complex ions with I- as follows: Hg2+ + I- HgI+ K1 = 1.0 × 108 HgI+ + I- HgI2 K2 = 1.0 × 105 HgI2 + I- HgI3- K3 = 1.0 × 109 HgI3- + I- HgI42- K4 = 1.0 × 108 A solution is prepared by dissolving 0.045 mol Hg(NO3)2 and 5.00 mol NaI in enough water to make 1.0 L of solution. Calculate the equilibrium concentration of [HgI42- ]. [HgI42- ] = ? M...

  • Calculate the molar concentration of Hg+2 ion. estion 1 For the aqueous (Hg(NH3)4]2+ complex has a...

    Calculate the molar concentration of Hg+2 ion. estion 1 For the aqueous (Hg(NH3)4]2+ complex has a Ky - 1,8 x 1019 at 25°C. Suppose equal volumes of 0.0082 M Hg(NO3)2 solution and 0.72 M NH3 solution were mixed. Calculate the equilibrium concentration (M) of aqueous (Please enter your answer is scientific notation. For example if you answer was 3.15 x 10. please enter 3.1585) Answer should be in 2 significant figures.

  • For the aqueous (Hg(NH3)4]2+ complex has a K - 1.8 x 1019 at 25°C. Suppose equal...

    For the aqueous (Hg(NH3)4]2+ complex has a K - 1.8 x 1019 at 25°C. Suppose equal volumes of 0.0082 M Hg(NO3)2 solution and 0.72 M NHg solution were mixed. Calculate the equilibrium concentration (M) of aqueous Hg2+ ion. (Please enter your answer is scientific notation. For example if you answer was 3.15 x 106, please enter 3.1585) Answer should be in 2 significant figures.

  • Question 1 For the aqueous (Hg(NH3)4]2+ complex has a Kt - 1.8 x 1019 at 25°C....

    Question 1 For the aqueous (Hg(NH3)4]2+ complex has a Kt - 1.8 x 1019 at 25°C. Suppose equal volumes of 0.0082 M Hg(NO3)2 solution and 0.72 M NH3 solution were mixed. Calculate the equilibrium concentration (Mof aqueous Hg2+ ion. (Please enter your answer is scientific notation. For example if you answer was 3.15 x 106, please enter 3.155) Answer should be in 2 significant figures

  • Mercury (II) forms the soluble neutral complex Hg(SCN)2 with the ligand SCN- The overall formation constant...

    Mercury (II) forms the soluble neutral complex Hg(SCN)2 with the ligand SCN- The overall formation constant B2 for binding of SCN to Hg2+ is 2.0 x 1017 Calculate the equilibrium molar concentrations of Hg2+ and SCN- and Hg(SCN)2 in a solution prepared by mixing 10 mL of 0.0200 M Hg2+ with 10 mL of 0.0200 M SCN". Make reasonable simplifying assumptions... and state them!

  • please explain thoroughly. thanks 4. Mercury (II) forms the soluble neutral complex Hg(SCN)2 with the ligand...

    please explain thoroughly. thanks 4. Mercury (II) forms the soluble neutral complex Hg(SCN)2 with the ligand SCN The overall formation constant B2 for binding of SCN to Hg?* is 2.0 x 10" Calculate the equilibrium molar concentrations of Hg2+ and SCN and Hg(SCN) in a solution prepared by mixing 10 mL of 0.0200 M Hg2+ with 10 mL of 0.0200 M SCN Make reasonable simplifying assumptions... and state them!

  • please explain. thanks 4. Mercury (II) forms the soluble neutral complex Hg(SCN)2 with the ligand SCN The overall fo...

    please explain. thanks 4. Mercury (II) forms the soluble neutral complex Hg(SCN)2 with the ligand SCN The overall formation constant B2 for binding of SCN to Hg?* is 2.0 x 10" Calculate the equilibrium molar concentrations of Hg2+ and SCN and Hg(SCN) in a solution prepared by mixing 10 mL of 0.0200 M Hg2+ with 10 mL of 0.0200 M SCN Make reasonable simplifying assumptions... and state them!

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT