Comment in case of any doubt.
The Hg2 ion forms complex ions with I' as follows: Hg2 HgI* K1 1.0x 108 HglIHg2...
Lunes CHEMWORK The Hg2+ ion forms complex ions with I as follows: Hg2+ + HgT+ HgI + 1 =Hg2 K1 = 1.0 108 K2=1.0 x 105 K3 -1.0 x 10° K4 = 1.0 * 108 Hgl2 + 1 + HgI3 HgI3 + 1 = Hg142 A solution is prepared by dissolving 0.057 mol Hg(NO3)2 and 5.00 mol Nal in enough water to make 1.0 L of solution. Calculate the equilibrium concentration of [Hg142]. (Hg142) = M Calculate the equilibrium concentration...
The Hg2+ ion forms complex ions with I- as follows: Hg2+ + I- HgI+ K1 = 1.0 × 108 HgI+ + I- HgI2 K2 = 1.0 × 105 HgI2 + I- HgI3- K3 = 1.0 × 109 HgI3- + I- HgI42- K4 = 1.0 × 108 A solution is prepared by dissolving 0.053 mol Hg(NO3)2 and 5.00 mol NaI in enough water to make 1.0 L of solution. Calculate the equilibrium concentration of [HgI42- ]. [HgI42- ] = M Calculate...
The Hg2+ ion forms complex ions with I- as follows: Hg2+ + I- HgI+ K1 = 1.0 × 108 HgI+ + I- HgI2 K2 = 1.0 × 105 HgI2 + I- HgI3- K3 = 1.0 × 109 HgI3- + I- HgI42- K4 = 1.0 × 108 A solution is prepared by dissolving 0.045 mol Hg(NO3)2 and 5.00 mol NaI in enough water to make 1.0 L of solution. Calculate the equilibrium concentration of [HgI42- ]. [HgI42- ] = ? M...
46. CHEMWORK 2+ ion forms complex ions with I' as follows: The Hg Hg2IHgI = 1.0 x 108 Кi HgI IHgl2 К2 3D 1.0 х 105 Hgl2 IHgI3 = 1.0 x 109 Кз— Hgl3I Hgl42- K4 1.0 x 108 A solution is prepared by dissolving 0.04 mol Hg(NO3)2 and 5.00 mol Nal in enough water to make 1.0 L of solution. Calculate the equilibrium concentration of [Hgl4] Hgl2- 1= М Calculate the equilibrium concentration of [I']. [I] Calculate the equilibrium...
Chapter 15 COC Reference NO,Aume that Out forms complex ions with X as follows Destion 18 Destion 19 Question 20 A solution is formed by mixing 50.0 mL of 10.9 MNX with 500 ml of 8.6 x 10-M Out (g) + X() OXog K; -10 x 10 CuX(aq) + X() - Cux, (a) K; -1.0 x 109 CuX;" ) + X (a) Cux,- (aq) K; -1.0 x 100 with an overall reaction Cu* (eq) +3X" () - CuX; (aq) -10x10'...
1. For the solutions that you will prepare in Step 7 of Part I, calculate the [FeSCN) using the equation CVC V2. Presume that all of the SCN ions react and therefore in Part of the experiment, mol of SCN=mol of FeSCN Record these values in the table below and in me data table for part / Standard solution. Beaker number [FeSCN2 2. Define equilibrium constant Keg. 3. Write the equilibrium constant expressions for each of the following chemical reactions:...
What is the coefficient of H.So, when the following equation is properly balanced with the smallest set of whole numbers? __Cas(PO4h + H2SO4 - Caso + HPO. A) 3 B) 8 C) 10 D) 11 2) What is the coefficient of H20 when the following equation is properly balanced with smallest set of whole numbers? ALC + H2O - AM(OH), + CHE A) 3 B) 4 C) 6 D) 12 E) 24 3) of the reactions below, which one is...