Homework Answers
(1)
When 1st is defective, 2nd is defective, then
P1 = (19/99)*(18/98)
if the 1st is non-defective, 2nd is defective, then
P2 = (80/99)*(19/98)
so the probability of 2nd being defective
P = P1+P2 = (19/99)*(18/98) + (80/99)*(19/98)
= .1919
(2)
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