Can i get help on part B please ?!?
here,
d1 = 6.57 cm = 0.0657 m
d2 = 1.06 m
theta = 53 degree
initial speed , u = 1.42 m/s
for horizontal direction
the time taken ,t = d2 /( u * cos(theta))
t = 1.06 /( 1.42 * cos(53))
t = 1.24 s
let the height of cliff be h
for vertical direction
- (h + d1 ) = u * sin(theta) * t - 0.5 * g * t^2
- ( h + 0.0657) = 1.42 * sin(53) * 1.24 - 0.5 * 9.81 * 1.24^2
solving for h
h = 6.07 m
the height of cliff is 6.07 m
Can i get help on part B please ?!? rarL A Use the information given to...
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