Question

2) You're standing on the uOttawa LRT platform watching the trains go by. Two train-cars attached together, each 10 m long, move past you. The first takes 2.10 s to pass you and the second takes 1.65 s. What is the constant acceleration of the train? 3) Your grandma is checking her phone while waiting for the bus at the stop in front of CBY building. A #95 bus passes her at a constant velocity of 5.2 m/s without stopping. When she looks up, the rear of the bus is already 10 m away and she realizes she needs to be on that bus and immediately chases after it on her new electric scooter. If her scooter can accelerate at a constant value of 1.1 m/s2 how far would she need to go to catch up with the rear of the bus and how fast would she be going when she does? Uo

Answer 1

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2 det grital velocity of the two train cars is = u mys Time taken by the first train to travel 10m = t1 = 2.1 S Time taken by the secand train to travel 20m = tż = (2.1+ 1.65) t₂ = 3.755 Use Secund Equation og motion for the first main car 2(1 = uti + Çat,? (lom) = u (2:15) + 1 9 (2-15) 2 10 = 2.1 () + 2.205(0) - -O use secand equation of molian fear the second hraincas 262. = u tz + Latz Beto (20m) = 4 (3.755) + 49 (3.75 s)? 20. = 3.75 (U) + 7-031(a) © Solving Equatten 09 © fan value of a. 20 = 3.75 (10-2:205-9) + 7.031 9 2.1. 9 = 0.693 m/s2 train is moving wim canstant accelena Hem å 20-693 m/s2 31 het us assume that A is the posodian of the rear end of the bus and G is the velore sentation of my grandma A a . K elom Initial sebration between A and G is d = 10m Velocity of the bus , VA = 5.2 m/s hetus assume that gt takes t secand for my grandma to catch the bus acceleration of the scooter, ag = 1.1 m/s2 distance bavelled by grandma sg = {gt? = {x1.1 x+2 distance travelled by bys , SA = 5.25 E ....Sg = SA +d! Ź x 1•1xt? = 5.25 +10 d B 14+2 - 5.2 t - 20 = O solving qudratic equation t = 11:0935, - 1.638 i t= 11.09355 (time can't be -ve) when my grandma catches the bus her speed will be lu) . = 4 + ag t = 0.+ (1-17 11-0935) 1ų = 12.203 M/S dislanu hravelled by my grand me to catch up with the neang the bus Sat = V 5.2+ Sq = 15.2 x 11.0935)+10 = 167.686 m