___ Pb(NO3)2 (aq) + ___KI (aq)
Show work on balancing the equasion
balancing equation Zn(s) +HCl(aq) HCl+ Na2SO3 HCl +ZnS Pb(NO3) +HCl
PI Au Hg Pb BI Po At Rn BALANCING EQUATION Oxclzlag) + O AgNO3(aq) OX(NO3)2(aq) + 0 Agci(s) DONE Contair H20 3 PROGRESS: 14% 8 equation on the wall display. E button when you think you MacBook Pro ps://ap/2.labster.com/simulation/aOK2X00000jGmBIUAS/ & 2 # 3 $ 4 5 6 7 8 9 0
2NaCl(aq) + Pb(NO3)2(aq)-NaNO3(aq) + PbCl2(s) How many formula units of Pb(NO3)2 would be needed in the above reaction to produce 555kg of PbCl2?
How many grams of PbCl2 are formed when 35.0 mL of 0.520 M KCl react with Pb(NO3)2? 2KCl(aq) + Pb(NO3)2(aq) → 2KNO3(aq) + PbCl2(s) How many grams of PbCl2 are formed when 35.0 mL of 0.520 M KCl react with Pb(NO3)2? 2KCl(aq) + Pb(NO3)2(aq) → 2KNO3(aq) + PbCl2(s) 10.1 g 25.3 g 5.06 g 15.2 g 2.53 g
Consider the balanced equation of KI reacting with Pb(NO3)2 to form a precipitate. 2KI(aq)+Pb(NO3)2(aq)⟶PbI2(s)+2KNO3(aq) What mass of PbI2 can be formed by adding 0.413 L of a 0.140 M solution of KI to a solution of excess Pb(NO3)2?
Formula of precipitate Pb(NO3)2(aq) + Kl(aq) → NaOH(aq) + KNO3(aq) → NaOH(aq) + Fe(NO3)2(aq) →
formula precipitation
Formula of precipitate SI(NO3)2(aq) + K3PO4(aq) Ba(NO3)2(aq) + MgSO4(aq) FeCl3(aq) + Pb(NO3)2(aq)-- H2SO4(aq) + Mg(OH)2(aq)— HNO3(aq) + Ba(OH)2(aq)— Formula of precipitate CuCl(aq) + K2CO3(aq) – KOH(aq) + Mn(NO3)2(aq) – Na2SO4(aq) + Ba(NO3)2(aq) -
KSP Questions. Please complete ICE tables and show work!
1. A 255mL sample of 0.00016M Pb(NO3)2(aq) was mixed with 456mL of 0.00023M Na SO4(aq). Provide the formula for the possible precipitate that could form? Will it precipitate be expected to form? Provide a complete balanced equation (not net). Don't forget phases. Ksp=1.7 x 108 3pts egn: Formula ppt= Does it form? Yes No
A solution of NaCl(aq) is added slowly to a solution of lead nitrate, Pb(NO3)2(aq) Pb ( NO 3 ) 2 ( aq ) , until no further precipitation occurs. The precipitate is collected by filtration, dried, and weighed. A total of 10.47 g PbCl2(s) 10.47 g PbCl 2 ( s ) is obtained from 200.0 mL 200.0 mL of the original solution. Calculate the molarity of the Pb(NO3)2(aq) Pb ( NO 3 ) 2 ( aq ) solution. concentration: M
Pb(NO3)2 (aq) + 2 KCl (aq) PbCl2 (s) + 2 KNO3 (aq) If 54.5mL of 3.82M Pb(NO3)2 reacts with 75.3mL of 5.89M KCl react: Find the limiting reactant. What is the mass of the precipitate that should be made? If this reaction has an efficiency of 78.4% what mass of the precipitate would typically be made?