Af constant volume, the temperature of 40 atom of gas was 190°c. The temperature is increased...

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Answer 1

Answer #1

1 . Apply Gay-Lussacs law We have , P,= 4.0 atm T,= 190°C T = 315°C Now, PT - 2 or Pr = PI TE = 4-batın x 315°C 190°C = 6.63

Answer 2

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