1) Given the following reactions: 2 P(s) + 3 Cl2(g) → AH = -635.1 kJ/mole 2...
1) Given the following reactions: 2 P(s) + 3 Cl2(g) → 2 PC13(1) AH = -635.1 kJ/mole PCL5 (s) → C12(8) + PC13(1) AH = +137.2 kJ/mole Determine the enthalpy of formation of PCL5 (s) -
4. (10 points)Given the following data: P4 (s) + 6 Cl2 (g) -------> 4 PC13 (1) P4 (8) + 10 Cl2 (g) -------> 4 PCls (g) AG° = -1088 kJ/mole P4 AG° = -1292 kJ/mole P4 Calculate AGº for the reaction PC13 (1) + Cl2 (g) -------> PCI; (g) (answer only 1 point)
Given the standard enthalpy changes for the following two reactions: (1) 2Pb(s) + O2(g) 2PbO(5) AH° = -434.6 kJ (2) Pb(s) + Cl2(g) →PbCl(s) AH° = -359.4 kJ what is the standard enthalpy change for the reaction: (3) 2 5C12(3) + O2(g)—2PbO(s) + 2Cl2(9) AH° = ?
3(20 pts) Consider the data: P4(s) + 6 Cl2(g) ----> 4 PC13(g) P4(s) + 5 O2(g) -----> P4010(s) PC13(g) + Cl2(g) ---> PCls(g) PC13(g) + 1/2O2(g) ----> C13PO(g) AH° (kJ/mol) -1226.6 -2967.3 -84.2 -285.7 Using only the above reaction data, compute the AHX of P4010(s) + 6 PCls(8) ----> 10 C13PO (g)
Calculate AH for the reaction PC13(1) + Cl2(g) → PC15(s) given the following data: Equation ΔΗ P4(s) + 6 Cl2(g) → 4 PC13(1) -1280 kJ P4(s) + 10 C12(g) → 4 PC1:($) -1774 kJ pt pt AH= 1 pt
Given the standard enthalpy changes for the following two reactions: (1) 2Fe(s) + O2(g)—2FeO(s) AH° = -544.0 kJ (2) Fe(s) + Cl2(g)—>FeCl2(5) AH° = -341.8 kJ what is the standard enthalpy change for the reaction: (3) 2FeCl2(S) + O2(g)—>2FeO(s) + 2Cl2(g) AH° = ? kJ Submit Answer Retry Entire Group 9 more group attempts remaining
32. Given the following data: A. P4(s)+ 6 Cl2(g)4 PCls(g) B. P4(s)+ 5 02(g) P4O10(s)AH=- 2967.3 C. PCls(g)+Cl2(g) PCIS(g) D. PCI3(g)+O2(g) ClaPO(g) AH-285.7 AH 1225.6 kJ AH=-84.2 Calculate AH for the reaction: P4O10(s)+6 PCI5(g) 10 CI3PO(g). Note when I solved this problem, I used 3 of the 4 data reactions, added them together, then used the fourth data reaction to get to the desired reaction. -B-6C+10D+A
Calculate the heat of formation for CaCO3(s) (kJ/mol) given that AH for the following reaction is +178 mole and instander enthalpies of formation: CaCO3(s) - CaO(s) + CO26) AHºf values (kJ/mol): CaO(s) = -635.1, CO2(g) = -393.5 Enter your answer as the nearest whole number with no units.
Consider these reactions, where M represents a generic metal. 1. AH, = -570.0 kJ 2. AH = -74.8 kJ 2 M(s) + 6 HCl(aq) + 2 MC1, (aq) + 3 H,() HCI(g) — HCl(aq) H_(8) + Cl2(g) + 2HCI(8) MCI,(s) -MCI, (aq) 3. AH = - 1845.0 kJ AHA = -365.0 kJ 4. Use the given information to determine the enthalpy of the reaction 2 M(s) + 3 CI,(g) — 2 MCI,(s) AH-
10. Given the following thermochemical data: 2 P(s) + 3 Cl, (g) → 2 PCI, (1) AH = -636 kJ/mol PCI, (1) PCI, (s) + C12 (8) AH = 138 kJ/mol compute the enthalpy of formation of PCI, (s), that is the enthalpy change for the reaction P(8) + 5/2 CI, (g) - PCI, (5) AH-? kJ/mol