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Calculate AH for the reaction PC13(1) + Cl2(g) → PC15(s) given the following data: Equation ΔΗ...
4. (10 points)Given the following data: P4 (s) + 6 Cl2 (g) -------> 4 PC13 (1)...
4. (10 points)Given the following data: P4 (s) + 6 Cl2 (g) -------> 4 PC13 (1) P4 (8) + 10 Cl2 (g) -------> 4 PCls (g) AG° = -1088 kJ/mole P4 AG° = -1292 kJ/mole P4 Calculate AGº for the reaction PC13 (1) + Cl2 (g) -------> PCI; (g) (answer only 1 point)
1) Given the following reactions: 2 P(s) + 3 Cl2(g) → 2 PC13(1) AH = -635.1...
1) Given the following reactions: 2 P(s) + 3 Cl2(g) → 2 PC13(1) AH = -635.1 kJ/mole PCL5 (s) → C12(8) + PC13(1) AH = +137.2 kJ/mole Determine the enthalpy of formation of PCL5 (s) -
1) PC13(1) + Cl2(g) → PCI;(g) Use equations (2) and (3) to calculate AH,xn of equation...
1) PC13(1) + Cl2(g) → PCI;(g) Use equations (2) and (3) to calculate AH,xn of equation (1): AH=-1280k (2) P4(5) + 6C12(3) — 4PCI3(0) (3) P4(s) + 10C12(g) → 4PC1g(8) AH = -1774k kJ
3(20 pts) Consider the data: P4(s) + 6 Cl2(g) ----> 4 PC13(g) P4(s) + 5 O2(g)...
3(20 pts) Consider the data: P4(s) + 6 Cl2(g) ----> 4 PC13(g) P4(s) + 5 O2(g) -----> P4010(s) PC13(g) + Cl2(g) ---> PCls(g) PC13(g) + 1/2O2(g) ----> C13PO(g) AH° (kJ/mol) -1226.6 -2967.3 -84.2 -285.7 Using only the above reaction data, compute the AHX of P4010(s) + 6 PCls(8) ----> 10 C13PO (g)
What is the equilibrium expression for the following reaction? PCl; (g) PC13 (9) + Cl2 (g)...
What is the equilibrium expression for the following reaction? PCl; (g) PC13 (9) + Cl2 (g) Keq [PC13][C12] [PC15] Keq = [PC13] [C12]2 [PC15] Keq [PC13] [PC15] Kea [PC13)(C12] [PC15] Keq [PC13) (C12] [PC15]
Given the following data: ΔΗ -92.2 N2(9)3H2(g) 2NH3(9) kJ N2(g)4H2(g) Cl2(g) - AH = -628.9 2NH4CI(s)...
Given the following data: ΔΗ -92.2 N2(9)3H2(g) 2NH3(9) kJ N2(g)4H2(g) Cl2(g) - AH = -628.9 2NH4CI(s) kJ NH3(g)HCI(g) NH4CI(s) = -176 kJ ΔΗ Find the AH of the following reaction: H2 (g)Cl2(g) -- 2HCI(g)
32. Given the following data: A. P4(s)+ 6 Cl2(g)4 PCls(g) B. P4(s)+ 5 02(g) P4O10(s)AH=- 2967.3...
32. Given the following data: A. P4(s)+ 6 Cl2(g)4 PCls(g) B. P4(s)+ 5 02(g) P4O10(s)AH=- 2967.3 C. PCls(g)+Cl2(g) PCIS(g) D. PCI3(g)+O2(g) ClaPO(g) AH-285.7 AH 1225.6 kJ AH=-84.2 Calculate AH for the reaction: P4O10(s)+6 PCI5(g) 10 CI3PO(g). Note when I solved this problem, I used 3 of the 4 data reactions, added them together, then used the fourth data reaction to get to the desired reaction. -B-6C+10D+A
7. Use the reaction enthalpies given below to determine AHºrxn for the following reaction: 8. Use...
7. Use the reaction enthalpies given below to determine AHºrxn for the following reaction: 8. Use the AHºf information provided to calculate AHºrxn for the following: P4(g) + 10 C12(g) + 4PC15(s) AHørxn = ? SO2Cl2(g) + 2 H2O(l) → 2 HCI(g) + H2804 Given: PC15(s) - PC13(g) + Cl2(g) P4(g) + 6 Cl2(g) - 4 PC13(g) AHørxn- +157 kJ Hºrxn=-1207 kJ AHºf (kJ/mol) SO2Cl2(g) H2O(1) HCl(g) H2S040) -364 -286 -92 -814 Voboty A) -2100. kJ B) -1835 kJ C)...
52) Use the standard reaction enthalpies given below to determine AHryn for the tonowe reaction P4()...
52) Use the standard reaction enthalpies given below to determine AHryn for the tonowe reaction P4() + 10 C12(e) → 4PC15(s) Hºrxn = ? Given: PC15(s) → PC13(g) + Cl2(e) AHørxn = +157 kJ P4(B) + 6 Cl2(e) → 4 PC13(g) AH*rxn=-1207 kJ A) -1835 kJ B) -1364 kJ C) -1050. kJ D) -1786 kJ E) -2100. kJ 53) Use the standard reaction enthalpies given below to determine AHørxn for the following reaction 4 SO3(e) — 4 S(s) + 6...
The equilibrium constant, Kc, for the following reaction is 83.3 at 500 K. PC13(g) + Cl2(g)...
The equilibrium constant, Kc, for the following reaction is 83.3 at 500 K. PC13(g) + Cl2(g) = PC15(g) Calculate the equilibrium concentrations of reactant and products when 0.389 moles of PC13 and 0.389 moles of Cl2 are introduced into a 1.00 L vessel at 500 K [PC13] = [Cl] = [PC15] - The equilibrium constant, Kc, for the following reaction is 5.10x10-6 at 548 K. NH4Cl(s) NH3(g) + HCl(g) Calculate the equilibrium concentration of HCl when 0.467 moles of NHACI(S)...
4. (10 points)Given the following data: P4 (s) + 6 Cl2 (g) -------> 4 PC13 (1) P4 (8) + 10 Cl2 (g) -------> 4 PCls (g) AG° = -1088 kJ/mole P4 AG° = -1292 kJ/mole P4 Calculate AGº for the reaction PC13 (1) + Cl2 (g) -------> PCI; (g) (answer only 1 point)
1) Given the following reactions: 2 P(s) + 3 Cl2(g) → 2 PC13(1) AH = -635.1 kJ/mole PCL5 (s) → C12(8) + PC13(1) AH = +137.2 kJ/mole Determine the enthalpy of formation of PCL5 (s) -
1) PC13(1) + Cl2(g) → PCI;(g) Use equations (2) and (3) to calculate AH,xn of equation (1): AH=-1280k (2) P4(5) + 6C12(3) — 4PCI3(0) (3) P4(s) + 10C12(g) → 4PC1g(8) AH = -1774k kJ
3(20 pts) Consider the data: P4(s) + 6 Cl2(g) ----> 4 PC13(g) P4(s) + 5 O2(g) -----> P4010(s) PC13(g) + Cl2(g) ---> PCls(g) PC13(g) + 1/2O2(g) ----> C13PO(g) AH° (kJ/mol) -1226.6 -2967.3 -84.2 -285.7 Using only the above reaction data, compute the AHX of P4010(s) + 6 PCls(8) ----> 10 C13PO (g)
What is the equilibrium expression for the following reaction? PCl; (g) PC13 (9) + Cl2 (g) Keq [PC13][C12] [PC15] Keq = [PC13] [C12]2 [PC15] Keq [PC13] [PC15] Kea [PC13)(C12] [PC15] Keq [PC13) (C12] [PC15]
Given the following data: ΔΗ -92.2 N2(9)3H2(g) 2NH3(9) kJ N2(g)4H2(g) Cl2(g) - AH = -628.9 2NH4CI(s) kJ NH3(g)HCI(g) NH4CI(s) = -176 kJ ΔΗ Find the AH of the following reaction: H2 (g)Cl2(g) -- 2HCI(g)
32. Given the following data: A. P4(s)+ 6 Cl2(g)4 PCls(g) B. P4(s)+ 5 02(g) P4O10(s)AH=- 2967.3 C. PCls(g)+Cl2(g) PCIS(g) D. PCI3(g)+O2(g) ClaPO(g) AH-285.7 AH 1225.6 kJ AH=-84.2 Calculate AH for the reaction: P4O10(s)+6 PCI5(g) 10 CI3PO(g). Note when I solved this problem, I used 3 of the 4 data reactions, added them together, then used the fourth data reaction to get to the desired reaction. -B-6C+10D+A
7. Use the reaction enthalpies given below to determine AHºrxn for the following reaction: 8. Use the AHºf information provided to calculate AHºrxn for the following: P4(g) + 10 C12(g) + 4PC15(s) AHørxn = ? SO2Cl2(g) + 2 H2O(l) → 2 HCI(g) + H2804 Given: PC15(s) - PC13(g) + Cl2(g) P4(g) + 6 Cl2(g) - 4 PC13(g) AHørxn- +157 kJ Hºrxn=-1207 kJ AHºf (kJ/mol) SO2Cl2(g) H2O(1) HCl(g) H2S040) -364 -286 -92 -814 Voboty A) -2100. kJ B) -1835 kJ C)...
52) Use the standard reaction enthalpies given below to determine AHryn for the tonowe reaction P4() + 10 C12(e) → 4PC15(s) Hºrxn = ? Given: PC15(s) → PC13(g) + Cl2(e) AHørxn = +157 kJ P4(B) + 6 Cl2(e) → 4 PC13(g) AH*rxn=-1207 kJ A) -1835 kJ B) -1364 kJ C) -1050. kJ D) -1786 kJ E) -2100. kJ 53) Use the standard reaction enthalpies given below to determine AHørxn for the following reaction 4 SO3(e) — 4 S(s) + 6...
The equilibrium constant, Kc, for the following reaction is 83.3 at 500 K. PC13(g) + Cl2(g) = PC15(g) Calculate the equilibrium concentrations of reactant and products when 0.389 moles of PC13 and 0.389 moles of Cl2 are introduced into a 1.00 L vessel at 500 K [PC13] = [Cl] = [PC15] - The equilibrium constant, Kc, for the following reaction is 5.10x10-6 at 548 K. NH4Cl(s) NH3(g) + HCl(g) Calculate the equilibrium concentration of HCl when 0.467 moles of NHACI(S)...
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