We need at least 10 more requests to produce the answer.
0 / 10 have requested this problem solution
The more requests, the faster the answer.
4. (10 points)Given the following data: P4 (s) + 6 Cl2 (g) -------> 4 PC13 (1)...
3(20 pts) Consider the data: P4(s) + 6 Cl2(g) ----> 4 PC13(g) P4(s) + 5 O2(g) -----> P4010(s) PC13(g) + Cl2(g) ---> PCls(g) PC13(g) + 1/2O2(g) ----> C13PO(g) AH° (kJ/mol) -1226.6 -2967.3 -84.2 -285.7 Using only the above reaction data, compute the AHX of P4010(s) + 6 PCls(8) ----> 10 C13PO (g)
Calculate AH for the reaction PC13(1) + Cl2(g) → PC15(s) given the following data: Equation ΔΗ P4(s) + 6 Cl2(g) → 4 PC13(1) -1280 kJ P4(s) + 10 C12(g) → 4 PC1:($) -1774 kJ pt pt AH= 1 pt
32. Given the following data: A. P4(s)+ 6 Cl2(g)4 PCls(g) B. P4(s)+ 5 02(g) P4O10(s)AH=- 2967.3 C. PCls(g)+Cl2(g) PCIS(g) D. PCI3(g)+O2(g) ClaPO(g) AH-285.7 AH 1225.6 kJ AH=-84.2 Calculate AH for the reaction: P4O10(s)+6 PCI5(g) 10 CI3PO(g). Note when I solved this problem, I used 3 of the 4 data reactions, added them together, then used the fourth data reaction to get to the desired reaction. -B-6C+10D+A
1) Given the following reactions: 2 P(s) + 3 Cl2(g) → AH = -635.1 kJ/mole 2 PC13(1) AH = +137.2 kJ/mole PCls (s) → Cl2(g) + PC1341 Determine the enthalpy of formation of PCs (s)
1) Given the following reactions: 2 P(s) + 3 Cl2(g) → 2 PC13(1) AH = -635.1 kJ/mole PCL5 (s) → C12(8) + PC13(1) AH = +137.2 kJ/mole Determine the enthalpy of formation of PCL5 (s) -
1) PC13(1) + Cl2(g) → PCI;(g) Use equations (2) and (3) to calculate AH,xn of equation (1): AH=-1280k (2) P4(5) + 6C12(3) — 4PCI3(0) (3) P4(s) + 10C12(g) → 4PC1g(8) AH = -1774k kJ
Use the standard reaction enthalpies given below to determine H°rxn for the following reaction: P4 (g) + 10 Cl2 (g) --> 4 PCl5 (s) ΔHreaction = ? Given: PCl5 (s) --> PCl3 (g) + Cl2 (g) ΔHreaction = +157 kJ P4 (g) + 6 Cl2 (g) --> 4 PCl3 (g) ΔHreaction = -1207 kJ Choices: A. -1835 kJ B. -1364 kJ C. -1050 kJ D. -1786 kJ E. -2100 kJ
age 1: Question 2 (34 points) Calculate A Hºrxn for the following reaction from the given data. PC15(g) + 4H2O(g) ---> H3PO4(1) + 5 HCl(g) A Hºrxn = ??? P4(s) + 10 Cl2(g) ---> 4 PC15(8) A Hºrxn = - 1499.6 kJ H2(g) + 1/2O2(g) ---> H2O(g) A Hºrxn = -241.8 kJ H2(g) + Cl2(g) ---> 2 HCl(g) A Hºrxn = -185.0 kJ 4 H3PO4(1) ---> P4010(s) + 6 H2O(g) A Hºrxn = +677.2 kJ : P4(s) + 5 O2()...
3. (20 pts) a. Consider the following reaction: PC15(g) z PC13(g) + Cl2(g) Using the following data find the AH°, 45°, and AG° at 534 K. Kºp 0.245 1.99 4.96 9.35 T(K) 485 534 556 574 b. For the reaction above state whether the equilibrium shifts to the left or the right (or neither) when the following changes are made in an equilibrium mixture at 25 °C. 1. Tis decreased at constant P 2. Vis decreased at constant T Some...
Given: PCl5(s) → PCl3(g) + Cl2(g) ΔH°rxn = + 157 kJ P4(g) + 6 Cl2(g) → 4 PCl3(g) ΔH°rxn = - 1207 kJ What is the standard-state enthalpy change for the following reaction? P4(g) + 10 Cl2(g) → 4PCl5(s)a -2100 kJb-1835 kJc-1364 kJD -1786 kJ