Question

age 1: Question 2 (34 points) Calculate A Hºrxn for the following reaction from the given data. PC15(g) + 4H2O(g) ---> H3PO4(

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Given Reaction is: PCs (8) + 4H₂O(g) H₃PO4 (1) + 5 Helig, Altren ? then add to make the net reaction same hearrange the given

Add a comment
Know the answer?
Add Answer to:
age 1: Question 2 (34 points) Calculate A Hºrxn for the following reaction from the given...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 7. Use the reaction enthalpies given below to determine AHºrxn for the following reaction: 8. Use...

    7. Use the reaction enthalpies given below to determine AHºrxn for the following reaction: 8. Use the AHºf information provided to calculate AHºrxn for the following: P4(g) + 10 C12(g) + 4PC15(s) AHørxn = ? SO2Cl2(g) + 2 H2O(l) → 2 HCI(g) + H2804 Given: PC15(s) - PC13(g) + Cl2(g) P4(g) + 6 Cl2(g) - 4 PC13(g) AHørxn- +157 kJ Hºrxn=-1207 kJ AHºf (kJ/mol) SO2Cl2(g) H2O(1) HCl(g) H2S040) -364 -286 -92 -814 Voboty A) -2100. kJ B) -1835 kJ C)...

  • 3(20 pts) Consider the data: P4(s) + 6 Cl2(g) ----> 4 PC13(g) P4(s) + 5 O2(g)...

    3(20 pts) Consider the data: P4(s) + 6 Cl2(g) ----> 4 PC13(g) P4(s) + 5 O2(g) -----> P4010(s) PC13(g) + Cl2(g) ---> PCls(g) PC13(g) + 1/2O2(g) ----> C13PO(g) AH° (kJ/mol) -1226.6 -2967.3 -84.2 -285.7 Using only the above reaction data, compute the AHX of P4010(s) + 6 PCls(8) ----> 10 C13PO (g)

  • 1) 2) 3) 4) C3H8(g) + 5 O2(g) = 3 CO2(g) + 4H2O(1) AH = -2220...

    1) 2) 3) 4) C3H8(g) + 5 O2(g) = 3 CO2(g) + 4H2O(1) AH = -2220 kJ Decreasing the temperature will result in shift the equilibrium to the right shift the equilibrium to the left Keq is decreased O no effect in shifting the equilibrium more information is needed Which of the following expressions is the correct equilibrium-constant expression for the reaction below? P4010(s) = P4(s) + 5 O2(g) [02]-5 O [0215 [P4010] [Pd][02] [P][0215 O [P4010] [P4010) [P][0,1175 A...

  • Calculate AH for the reaction PC13(1) + Cl2(g) → PC15(s) given the following data: Equation ΔΗ...

    Calculate AH for the reaction PC13(1) + Cl2(g) → PC15(s) given the following data: Equation ΔΗ P4(s) + 6 Cl2(g) → 4 PC13(1) -1280 kJ P4(s) + 10 C12(g) → 4 PC1:($) -1774 kJ pt pt AH= 1 pt

  • 1) 2) 3) C3H8(g) + 5 O2(g) = 3 CO2(g) + 4H2O(1) AH = -2220 kJ...

    1) 2) 3) C3H8(g) + 5 O2(g) = 3 CO2(g) + 4H2O(1) AH = -2220 kJ Decreasing the temperature will result in shift the equilibrium to the right shift the equilibrium to the left Keq is decreased O no effect in shifting the equilibrium more information is needed Which of the following expressions is the correct equilibrium-constant expression for the reaction below? P4010(s) = P4(s) + 5 O2(g) [02]-5 O [0215 [P4010] [Pd][02] [P][0215 O [P4010] [P4010) [P][0,1175 A proposed...

  • Physical Chemistry Question please show work Given the reactions (1) and (2) below, determine the following....

    Physical Chemistry Question please show work Given the reactions (1) and (2) below, determine the following. He =-184.62 k, mol-1 (1) H2(g) + Cl2(g) → 2 HCl(g) (2) 2 H2(g) + O2(g) → 2 H2O(g) (3) 4 HCl(g) + O2(g) → Cl2(g) + 2 H2O(g) A,He =-483.64 k, mol-1 (a) 4,He and 4ue for reaction (3) -114.4 kJ mol-1 Aue mol-1 (b) ΔfHe for both HCI(g) and H2O(g) all at 298K. HCI(g) Δ(He kJ mol-1 kJ mol-1

  • Part 1) Use the following equations to calculate the heat of the reaction for the formation...

    Part 1) Use the following equations to calculate the heat of the reaction for the formation of ethane (C2H6). C2H6(g) + 7/2 O2(g) → 2CO2(g) + 3 H2O(l) ∆ Ho = -1560 kJ C(gr) + O2(g) → CO2(g) ∆ Ho = -394 kJ H2(g) + 1/2 O2(g) → H2O(l) ∆ Ho = -286 kJ Calculate ∆Ho for the following reaction: 2 C(gr) + 3H2(g) → C2H6(g) ethane Use kJ for your answer. ΔHo = Part 2) Find the heat of...

  • Calculate the value of AHº for the reaction 2 H2O2 (1) + 2 H20 (1) +...

    Calculate the value of AHº for the reaction 2 H2O2 (1) + 2 H20 (1) + O2 (9) given the following thermochemical equations: H2(g) + 1/2O2(g) → H2O (1) AH° = -286 kJ H2(g) + O2(g) → H2O2 (1) AH° = - 188 kJ - 196 kJ - 474 kJ + 196 kJ 98 kJ

  • 52) Use the standard reaction enthalpies given below to determine AHryn for the tonowe reaction P4()...

    52) Use the standard reaction enthalpies given below to determine AHryn for the tonowe reaction P4() + 10 C12(e) → 4PC15(s) Hºrxn = ? Given: PC15(s) → PC13(g) + Cl2(e) AHørxn = +157 kJ P4(B) + 6 Cl2(e) → 4 PC13(g) AH*rxn=-1207 kJ A) -1835 kJ B) -1364 kJ C) -1050. kJ D) -1786 kJ E) -2100. kJ 53) Use the standard reaction enthalpies given below to determine AHørxn for the following reaction 4 SO3(e) — 4 S(s) + 6...

  • Given these reactions, where X represents a generic metal or metalloid 1) H2(g)+12O2(g)⟶H2O(g)Δ?1=−241.8 kJ1) H2(g)+12O2(g)⟶H2O(g)ΔH1=−241.8 kJ...

    Given these reactions, where X represents a generic metal or metalloid 1) H2(g)+12O2(g)⟶H2O(g)Δ?1=−241.8 kJ1) H2(g)+12O2(g)⟶H2O(g)ΔH1=−241.8 kJ 2) X(s)+2Cl2(g)⟶XCl4(s)Δ?2=+157.3 kJ2) X(s)+2Cl2(g)⟶XCl4(s)ΔH2=+157.3 kJ 3) 12H2(g)+12Cl2(g)⟶HCl(g)Δ?3=−92.3 kJ3) 12H2(g)+12Cl2(g)⟶HCl(g)ΔH3=−92.3 kJ 4) X(s)+O2(g)⟶XO2(s)Δ?4=−769.5 kJ4) X(s)+O2(g)⟶XO2(s)ΔH4=−769.5 kJ 5) H2O(g)⟶H2O(l)Δ?5=−44.0 kJ5) H2O(g)⟶H2O(l)ΔH5=−44.0 kJ what is the enthalpy, Δ?,ΔH, for this reaction? XCl4(s)+2H2O(l)⟶XO2(s)+4HCl(g)

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT