1) PC13(1) + Cl2(g) → PCI;(g) Use equations (2) and (3) to calculate AH,xn of equation...
Calculate AH for the reaction PC13(1) + Cl2(g) → PC15(s) given the following data: Equation ΔΗ P4(s) + 6 Cl2(g) → 4 PC13(1) -1280 kJ P4(s) + 10 C12(g) → 4 PC1:($) -1774 kJ pt pt AH= 1 pt
4. (10 points)Given the following data: P4 (s) + 6 Cl2 (g) -------> 4 PC13 (1) P4 (8) + 10 Cl2 (g) -------> 4 PCls (g) AG° = -1088 kJ/mole P4 AG° = -1292 kJ/mole P4 Calculate AGº for the reaction PC13 (1) + Cl2 (g) -------> PCI; (g) (answer only 1 point)
1) Given the following reactions: 2 P(s) + 3 Cl2(g) → 2 PC13(1) AH = -635.1 kJ/mole PCL5 (s) → C12(8) + PC13(1) AH = +137.2 kJ/mole Determine the enthalpy of formation of PCL5 (s) -
3(20 pts) Consider the data: P4(s) + 6 Cl2(g) ----> 4 PC13(g) P4(s) + 5 O2(g) -----> P4010(s) PC13(g) + Cl2(g) ---> PCls(g) PC13(g) + 1/2O2(g) ----> C13PO(g) AH° (kJ/mol) -1226.6 -2967.3 -84.2 -285.7 Using only the above reaction data, compute the AHX of P4010(s) + 6 PCls(8) ----> 10 C13PO (g)
Wrto the equilibrium expression for each chemical equation: PCs(a) =PC13(+ Cl2(a) K [PC] [PC1,][Cl] K_[PCI,][CI] [PCI) OR_[PC][CI] [PC] [PCI,1 K PC1,C, QUESTION 18 Norane ( 20 ) a hydrocarbon that can be bumed as fol. The standard host of combustion is shown in the chemical equation below: CH206) +140x9 00260 +10H,O,,AH = -6125.21kJ/mol if 130g of onane combusts, how much heat is released? -6040 kJ 6040 -6211 6211 kJ QUESTION 19 30 * )=140x104m. Calculate (OH) given 7.14 M 140x100...
1) Given the following reactions: 2 P(s) + 3 Cl2(g) → AH = -635.1 kJ/mole 2 PC13(1) AH = +137.2 kJ/mole PCls (s) → Cl2(g) + PC1341 Determine the enthalpy of formation of PCs (s)
How could I solve this? 5. For the reaction: PCI;(g) + Cl2(g) + PC13(g). If Kp =1.05 at 250°C. What is the value of Kc?
10. Given the following thermochemical data: 2 P(s) + 3 Cl, (g) → 2 PCI, (1) AH = -636 kJ/mol PCI, (1) PCI, (s) + C12 (8) AH = 138 kJ/mol compute the enthalpy of formation of PCI, (s), that is the enthalpy change for the reaction P(8) + 5/2 CI, (g) - PCI, (5) AH-? kJ/mol
Phosphorus pentachloride decomposes according to the chemical equation PC15(g) PC13(g) + Cl2 (g) Kc = 1.80 at 250° C A 0.475 mol sample of PCI, (g) is injected into an empty 4.90 L reaction vessel held at 250° C. Calculate the concentrations of PCI, (g) and PCI,(g) at equilibrium. [PCls] [PCl3]
The equilibrium constant, K., for the following reaction is 1.20 10-2 at 500 K. PCI(8) =PC13(g) + Cl2(g) Calculate the equilibrium concentrations of reactant and products when 0.363 moles of PC13() are introduced into a 1.00 L vessel at 500 K M [PC131 = [PC13] - [Cl] M M