4. A solid sphere of mass 2 ks and radius of 0.2 m starts from rest...
A sphere of radius r =34.5 cm and mass m = 1.80 kg starts from rest and rolls without slipping down a 30.0∘ incline that is 10.0 m long. Calculate its translational speed when it reaches the bottom. Calculate its rotational speed when it reaches the bottom. What is the ratio of translational to rotational kinetic energy at the bottom?
A sphere of radius r =34.5 cm and mass m = 1.80 kg starts from rest and rolls without slipping down a 30.0∘ incline that is 10.0 m long. Calculate its translational speed when it reaches the bottom. Calculate its rotational speed when it reaches the bottom. What is the ratio of translational to rotational kinetic energy at the bottom?
A solid sphere of uniform density starts from rest and rolls without slipping a distance of d = 2 m down a θ = 20° incline. The sphere has a mass M = 5.8 kg and a radius R = 0.28 m. 1. Of the total kinetic energy of the sphere, what fraction is translational? KE tran/KEtotal 2)What is the translational kinetic energy of the sphere when it reaches the bottom of the incline? KE tran = 3. What is the...
A sphere of radius r =34.5 cm and mass m = 1.80 kg starts from rest and rolls without slipping down a 30.0? incline that is 10.0m long. Part A Calculate its translational speed when it reaches the bottom. v= Part B Calculate its rotational speed when it reaches the bottom. Express your answer using three significant figures and include the appropriate units. w = Part C What is the ratio of translational to rotational kinetic energy at the bottom?...
A sphere of radius r =34.5 cm and mass m = 1.80 kg starts from rest and rolls without slipping down a 30.0° incline that is 10.0 m long.A) Calculate its translational speed when it reaches the bottom.B) Calculate its rotational speed when it reaches the bottom. C) What is the ratio of translational to rotational kinetic energy at the bottom? D) Avoid putting in numbers until the end so you can answer: do your...
A solid homogeneous sphere of mass M = 4.70 kg is released from rest at the top of an incline of height H=1.21 m and rolls without slipping to the bottom. The ramp is at an angle of θ = 27.7o to the horizontal. a) Calculate the speed of the sphere's CM at the bottom of the incline. b) Determine the rotational kinetic energy of the sphere at the bottom of the incline.
A 3.0 kg solid sphere (radius = 0.20 m ) is released from rest at the top of a ramp and allowed to roll without slipping. The ramp is 0.90 m high and 5.5 m long. A.) When the sphere reaches the bottom of the ramp, what is its total kinetic energy? B.) When the sphere reaches the bottom of the ramp, what is its rotational kinetic energy? C.) When the sphere reaches the bottom of the ramp, what is...
A solid sphere rolls in released from rest and rolls down an incline plane, which is 2.0 m long and inclined at a 30° angle from the horizontal. (a) Find its speed at the bottom of the incline. (Remember that the kinetic energy in rolling motion is the translational kinetic energy ½ Mv2 of the center, plus the rotational K.E. ½ Iω2 about the center. Also remember that v = ωr if the sphere rolls without slipping.) (b) Find the...
An 8.10-cm-diameter, 300 g solid sphere is released from rest at the top of a 1.60-m-long, 16.0 ? incline. It rolls, without slipping, to the bottom. a)What is the sphere's angular velocity at the bottom of the incline? b)What fraction of its kinetic energy is rotational?
2. Rolling down the hill (a) A solid cylinder of mass 1.0 kg and radius 10 cm starts from rest and rolls without slipping down a 1.0 m-high inclined plane. What is the speed of the cylinder when it reaches the bottom of the inclined plane? (b) How about a solid sphere of the same mass and radius? (c) How about a hoop of the same mass and radius? (d) Which of the above objects is moving fastest when it...