a) Find n for a 90% confidence interval for p
with bound on the error of estimation (margin of error) = 0.038
using an estimate of p = 0.7. (Round up to the nearest
whole number.) NOTE: If you have the 98% or the 99%
confidence interval for this question, PLEASE READ THE INSTRUCTIONS
at the top of the assignment.
b) Find the conservatively large value for n using the
same confidence interval and bound on the error of estimation
(margin of error) mentioned in part a with no estimate of
p. (Round up to the nearest whole number.)
* Sample size = Z2/2 * p (1 - p) / E2
a)
Sample size = 1.64492 * 0.7 * 0.3 / 0.0382
= 393.49
n = 394 (Rounded up to nearest integer)
b)
When prior estimate for proportion is not specified then p = 0.50
Sample size = 1.64492 * 0.5 * 0.5 / 0.0382
= 468.43
n = 469 (Rounded up to nearest integer)
a) Find n for a 90% confidence interval for p with bound on the error of...
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