Find n for a 90% confidence interval for p
with E = 0.036 using an estimate of p = 0.75.
(Round up to the nearest whole number.)
Find n for a 90% confidence interval for p with E = 0.036 using an estimate...
a) Find n for a 90% confidence interval for p with bound on the error of estimation (margin of error) = 0.038 using an estimate of p = 0.7. (Round up to the nearest whole number.) NOTE: If you have the 98% or the 99% confidence interval for this question, PLEASE READ THE INSTRUCTIONS at the top of the assignment. b) Find the conservatively large value for n using the same confidence interval and bound on the error of estimation...
1) Find n for a 99% confidence interval for p with bound on the error of estimation (margin of error) = 0.03 using an estimate of p = 0.85. (Round up to the nearest whole number.) 2)Find the conservatively large value for n using the same confidence interval and bound on the error of estimation (margin of error) mentioned in part a with no estimate of p. (Round up to the nearest whole number.)
Determine the sample size n needed to construct a 90% confidence interval to estimate the population proportion when p = 0.65 and the margin of error equals 7%. n= (Round up to the nearest integer.)
A 90% confidence interval for p is given as (0.37,0.63). How large was the sample used to construct this interval? n(Round up to the nearest observation.)
is pos5100 n= by A researcher wishes to estimate with 90% confidence, the population proportion of adults who support labeling logislation for genetically modified organisms (CMOS) Her estimate must be accurate within 6% of the true proportion io (a) No preliminary estimate is available. Find the minimum sample size needed. (b) Find the minimum sample size needed, using a prior study that found that 73% of the respondents said they support labeling legislation for GMOs (c) Compare the results from...
Construct the confidence interval for the population mean μ c: 0.95, x-16.8, σ: 9.0, and n-100 A 95% confidence interval for μ is OD (Round to one decimal place as needed.) 6.1.27 Use the confidence interval to find the margin of error and the sample mean (1.58,2.06) The margin of error is (Round to two decimal places as needed) 6.1.31 Find the minimum sample size n needed to estimate μ for the given values of c, o, and E. cz...
Assume that you want to construct a 95% confidence interval estimate of a population mean. Find an estimate of the sample size needed to obtain the specified margin of error for the 95% confidence interval. The sample standard deviation is given below. Margin of error =$5,standard deviation=$25 The required sample size is ????? (Round up to the nearest whole number as needed.)
Assume that you want to construct a 95% confidence interval estimate of a population mean. Find an estimate of the sample size needed to obtain the specified margin of error for the 95% confidence interval. The sample standard deviation is given below. Margin of errorequals $3, standard deviationequals $23 The required sample size is nothing . (Round up to the nearest whole number as needed.)
Assume that you want to construct a 95% confidence interval estimate of a population mean. Find an estimate of the sample size needed to obtain the specified margin of error for the 95% confidence interval. The sample standard deviation is given below. Margin of error equals=$66, standard deviation equals=$2222 The required sample size is _____. (Round up to the nearest whole number as needed.)
8.1.5 Question Help Determine the 95% confidence interval estimate for the population mean of a normal distribution given n = 100, o = 133, and x = 1,500 The 95% confidence interval for the population mean is from to (Round to two decimal places as needed. Use ascending order.) 8.1.14-T Question Help As a follow-up to a report on gas consumption, a consumer group conducted a study of SUV owners to estimate the mean mileage for their vehicles. A simple...