Question

Question 12 1 points Save Answer xperimental drug for treatment of pain after surgery to a sample of 16 subjects. In order to include pationts from all 3 hospitals in A research group administered a new e the area five subjects were randomly drawn from surgery patients at each of the f ampled equal to 16. The researchers then recorded the average form a weighted average and estimate the mean time for all were drawn from the third hospital, making the meon tine for urberct maes bis in each group. They wil use the data obtained to surgery patients 5897 47 72 54 79 6 38 40 0 75 53 3 007 The underlying assumption in this type of sampling method (lem 18) is hat var iablity within each group wit be compared to vanabety between groups small large

Answer 1

Y	Hospital
58	1
97	1
47	1
72	1
54	1
79	2
67	2
38	2
46	2
66	2
73	3
57	3
38	3
60	3
6	3
7	3

One-way ANOVA: Y versus Hospital

Source	DF	SS	MS	F	P
Hospital (Between)	2	1956	978	1.89	0.190
Error (Within	13	6715	517
Total	15	8671

S = 22.73 R-Sq = 22.56% R-Sq(adj) = 10.65%

The estimated P-value is 0.190 and less than 0.05 level of significance. Hence, there is no significant difference between the mean time of surgery at this three hospital at 0.05 level of significance.

The underlying assumption in this type of sampling method is that the variability within each group will be equal compared to variability between groups.