Question

A rocket leaves the launch pad with constant acceleration 43.1 m/s/s. What is its altitude after 43.2 seconds, in km?

Answer 1

Now the acceleration of the rocket a= 43.1m/s^2

Altitude attend by the rocket d=?

Time required to attend the altitude d=43.2 sec

Now by the kinematics equation

d= 1/2*a*t + V*t ....................(1)

Here V= initial velocity of rocket = 0 m/s

therefore

(1) ...> d= 1/2* 43.1*43.2 + 0

d= 930.96 m

d= 0.93096 km

Hence altitude attend by the rocket d= 0.93096 km