Question

7. How are these two compounds related to each other: same compound, structural isomers, enantiomers diastereomers? сH, сн, Answer OH HO н- H он но -н Н- CH, CH, 8. How are these two compounds related to each other: same compound, structural isomers, enantiomers, diastereomers? сH,он CH,OH Answer: Но Н- Он н Н OH но- -н CH сH, 9. (R)-tartaric acid has a specific rotation of +12.0 degrees. a) What is the specific rotation of (S)-tartaric acid? b) What is the specific rotation of a mixture of 68 % (R))-tartaric acid and 32 % ( S) -tartaric acid? Show all work c) What is the percent composition of a mixture of (R)- and (S)-tartaric acid with a specific rotation of 6.0 degrees. Show all work

Answer 1

сHg A CH₂ tot 1800 H2E11 H- OH 10-Ft CH3 Eltz Thus, they are same compound. CH₂OHE CHROH To th oft Hot A CA E CH3 there two compounds are mirror image to each other. This They are enantiomer Pimage H

I a) (B)-tartaric acid has specific rotation +12° Thus (s)-tastaric acid has specific rotation of -120, b) Now, a mixture contains 68% (B) - and 32% s- tartaric acid. This specific rotation GOX G212 + 32X (-) 12 - 100 = +4.32 e Let the mixture contains x% (B) - tartaric acid. Thus % of (s)- tartaric acid (100-2 Thus, specific rotation, xx 12 - (100-x) x 12 = 6 100 7 122-1200 +122= 600 * 242= 600 +1200 = 1800 az 1800 = 75 - 24 Thus, 75% (B)- tartaric acid & 25% (SI- tartaric acid