Let volume be 1 L
volume , V = 1 L
Given:
M. =0.85 mM = 8.5*10^-4 M
use:
number of mol,
n = Molarity * Volume
= 8.5*10^-4*1
= 8.5*10^-4 mol
Molar mass of Pb = 207.2 g/mol
use:
mass of Pb,
m = number of mol * molar mass
= 8.5*10^-4 mol * 2.072*10^2 g/mol
= 0.1761 g
So,
Concentration = 0.1761 g/L
Concentration = 176.1 mg/L
Answer: 1.8*10^2 mg/L
AMot of Lleol: L00xLD6 =L06 0.063 88 ppm 18 ppm d. Casa o.oooL693 LOG a. 880...
need help with the rest of the table
EXPERIMENT 10 DETERMINATION OF THE ELECTROCHEMICAL SERIES PURPOSE To determine the standard cell potential values of several electrochemical coll INTRODUCTION The basis for an electrochemical cell is an oxidation reduction Corredor be divided into two half reactions reaction. This reaction can Oxidation half reaction Gloss of electrons) takes place at the anode, which is the positive electrode that the anions migrate to Chence the name anode) Reduction half reaction (gain of electrons)...