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What volume of 0.829 M KOH solution is required to make 3.54 L of a solution with pH of 12.5? Express your answer with the ap

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Answer #1

Volume needed = 0.135L or 135 ml

Explanation:

pOH + pH = 14

pH = -log[H+]

And pOH = -log [ OH​​​​​-]

No. of moles = Molarity × volume

I.e n = CV

pH = 12.5 pOH = 14-ph pon = 14- 12.5 = 105 And low por = -log[104] [on-] = 10 -POH [OH-] = 10-15 = 316 X10 - 2M Molarity of s

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