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A chemist wants to make 6.0 L of a 0.280 mol L1 CaCl, solution Part A What mass of CaCl2 (in grams) should the chemist use? E
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Ca Cl Cg) Amount of 1 molasity = molaa maSS of Cacl. (9/mol) Nol. (dm3) 0.280 × 110.98 メ G :. Amoun) of Cacla (9)= 18G.4 g

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A chemist wants to make 6.0 L of a 0.280 mol L1 CaCl, solution Part A What mass of CaCl2 (in grams) should the ch...
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