Before answering the question we need to identify the type of distribution the sample belongs to. To identify that lets look at the information available to us.
n = 96 ,sample size
mean of the population = 24.8
mean of the sample = 25.6
standard deviation of the population = 2.9
confidence interval = 95%
Since the sample size is greater than 30 and standard deviation of the population is known we can use normal distribution.
To find 95% confidence interval the following formula can be used.
calculation of standard error and z value value is given in the following figure
calculation of z value is as follows
consider the above normal distribution. Since normal distribution is symmetrical, it can be divided into two parts of 0.5 each as shown in the above image. 95% confidence interval mean, 5% level if significance. Since it is two tailed test, there will be 2.5% (5%/2) alpha value on each tail.
The shaded region depicts alpha value of 2.5% which equals 0.025. consider the right side of tail. To find area of white region simply subtract 0.025 from 0.5, which gives the value 0.475. Now take z table look for 0.475 in table of values which should give the z value as 1.96.
Now plug these values on the formula for confidence interval. Look the following image.
95% confidence interval for mean age of men marry since 2000 is 25.01 and 26.19.
b) A confidence interval is a range of values in which actual value is expected to lie. The 95% confidence interval for the above question means that there is a 95% probability that that the population mean lies in the range 25.01 and 26.19.
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