Data from the Office for National Statistics show that the mean age at which men in Great Britain get married was 33.0. A news reporter noted that this represents a continuation of the trend of waiting until a later age to wed. A new sample of 47 recently wed British men provided their age at the time of marriage. These data are contained in the Excel Online file below. Construct a spreadsheet to answer the following questions. Open spreadsheet Do these data indicate that the mean age of British men at the time of marriage exceeds the mean age in 2013? Test this hypothesis at . What is your conclusion? Use the obtained rounded values in your calculations. Sample mean: 33.11 years (to 2 decimals) Sample standard deviation: 4.7468 years (to 4 decimals) -value: 0.154 (to 3 decimals) -value: (to 3 decimals) Because -value , we . There is evidence to conclude that the mean age at which British men get married exceeds what it was in 2013. Excel giving me wrong p value.
Find me the P- Value
Data set
25
30
30
33
34
34
38
37
29
39
30
29
37
26
30
34
39
26
28
34
35
40
25
35
37
31
35
25
40
40
32
34
35
28
38
37
39
31
37
37
39
34
39
30
25
29
27
Solution:
Here, we have to use one sample t test for population mean.
H0: µ = 33 versus Ha: µ > 33
This is an upper tailed or right tailed test.
From given data, we have
Xbar = 33.11
S = 4.7468
n = 47
df = n – 1 = 46
We assume α = 0.05
Test statistic formula is given as below:
t = (Xbar - µ)/[S/sqrt(n)]
t = (33.11 – 33)/[4.7468/sqrt(47)]
t = 0.11/ 0.6924
t = 0.1589
P-value = 0.4372
(by using t-table or excel)
P-value > α = 0.05
So, we do not reject the null hypothesis
There is insufficient evidence to conclude that the mean age at which British men get married exceeds what it was in 2013.
Data from the Office for National Statistics show that the mean age at which men in...
Age Formulas 30 Sample size 47 38 27 Sample mean (2 decimals) 31.51 =AVERAGE(A:A) 35 26 Sample Standard Deviation (4 decimals) 4.1852 =STDEV.S(A:A) 36 29 Hypothesized Mean 32 34 33 Test Statistic (3 decimals) -0.802 =(D4-D8)/(D6/SQRT(D2)) 33 29 Degrees of Freedom 46 =D2-1 31 40 p-value (3 decimals) need this need this 25 35 Level of Significance (Alpha) 0.05 32 27 Reject Null Hypothesis? #N/A 31 36 34 34 32 31 31 32 30 39 25 29 31 37 37...
1. Between 1900 and 2000, then mean age at which men in the US (who marry) get married for the first time had a mean of 24.8 years. The historical and current standard deviation of age of first marriage is 2.9 years. Since 2000, for a sample of 96 men, the mean age of marriage is 25.6 years. Find the 95% Confidence interval for the mean age men marry since 2000. a. What does the confidence interval tell us about...
Do the Academy Awards involve discrimination based on age? Listed below are the ages of actresses and actors at the times that they won Oscars in the Best Actress and Best Actor categories. the ages are listed in order, beginning with the first Academy Awards ceremony in 1928. (Note: in 1968 there was a tie in the Best Actress category, and the mean of the two ages is used; in 1932 there was a tie in the Best Actor category,...
2. In making aluminum castings into alternator housings, an average of 3.5 ounces per casting must be trimmed off and recycled as a raw material at the DAVID remanufacturing plant. A new manufacturing procedure has been proposed to reduce the amount of aluminum that must be recycled in this way. For a sample of 11 castings made with the new process the sample mean is 3.043 and sample standard deviation is 0.507. Using an appropriate hypothesis test, does the new...
These are my instructions: Your data should have been read in from the data file and stored into an array. Next you need to calculate the following and display in a single Message box: Average score Highest score Lowest score Mode of the scores Your program should be written using methods and should be well documented internally and externally. Your output should be displayed using Message boxes. This is the .text file to use with the instructions: 20 21 22...
Records from a random sample of 40 couples applying for a marriage license in Denver yielded the following ages for the 40 women in years: 19 20 20 20 21 21 22 22 23 23 24 24 24 25 25 25 25 25 26 28 29 29 29 29 30 30 30 31 31 31 31 32 33 35 35 36 38 40 43 46. Construct a 99% confidence interval for the mean of the age of women getting married...
Sample Data Sample Data Hour Sample Taken Hour Sample Taken 1 4 5 X 1 3 1 42 2 3 4 5 6 2 39 36 25 60 28 53 22 56 41 34 43 45 59 42 36 40 45 39 48 26 42 34 61 48 45 29 3 31 61 38 40 54 26 38 42 37 41 53 37 47 41 37 29 20 26 43 38 33 37 37 35 33 36 41 25 37...
Obs # Age Obs # Age Obs # Age Obs # Age Obs # Age 1 2019 11 2019 21 1976 31 2019 41 2006 2 1998 12 2019 22 2013 32 2018 42 2013 3 2019 13 2019 23 2019 33 2019 43 1982 4 1995 14 1980 24 1994 34 1997 44 2019 5 2018 15 2019 25 1979 35 2015 45 1988 6 2011 16 2016 26 1974 36 2019 46 2019 7 1974 17 1998 27...
Obs # Age Obs # Age Obs # Age Obs # Age Obs # Age 1 2019 11 2019 21 1976 31 2019 41 2006 2 1998 12 2019 22 2013 32 2018 42 2013 3 2019 13 2019 23 2019 33 2019 43 1982 4 1995 14 1980 24 1994 34 1997 44 2019 5 2018 15 2019 25 1979 35 2015 45 1988 6 2011 16 2016 26 1974 36 2019 46 2019 7 1974 17 1998 27...
The data in ‘Problem 4’ show the top 30 home run totals in each League in Major League Baseball in 2018. Use Excel to perform the appropriate test to see if the American League’s top home run hitters had a higher average number of home runs than the top National League home run hitters did. Assume both data sets come from normally distributed populations. one tailed or two: Test statistic: p-value: decision: Did AL Average more HR than NL Did:...