Question

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Problem 1 (25 pts) Starting from rest, a truck drags a 1225. kg crate 160. m up a 5.50° incline with a constant force of 6.25 kN directed parallel to the plane. The friction coefficient between the sled and surface is plk - 0.375. doton brood 122 sky 6250N a) Calculate the work done on the crate by the truck. b) Calculate the work done on the crate by the normal force. c) Calculate the work done on the crate by gravity. d) Calculate the work done on the crate by friction. e) Use the Work-Energy Theorem to calculate the speed of the crate after 160 m.

Answer 1

7 Work done on crate W = Fd cose Where 0 = 0 because force and displacement is in game sina direction ingreso 20 Tod - - - - hence wid= 6.25 X160 XCOS(O) kq = 1000ky Am F = force de to truck N = Normal force fonction farce = f= h, N= uleing use b.) again wd. = Fd cose and hese O= 90° because normal force is perpendiculas to displacoment wida 6.25x160 X Cos(90) on again wid = Fdcoso and 0,= 180° Wd a masing.docosa, = 626x 122589.8 8in(5.5).160.coiso) wd=-18401ky | - doy again wida Fid coso solle modeos o - 0.375X 1225x9.8x160 x cos (5.5) 716.9 € ky e) Apply werk energy theosem wodewock. + wodymillion + Walymarily = _19 6-38 – 18401)X103 = 4 x122.5% VL - V = 1271