8)
a) The reaction is endothermic. This is because ΔHrxn < 0.
b) The reverse reaction of above equation can be written as
MgO(s) + CO2(g) --> MgCO3(s) ΔHrxn = -117.3 kJ
Since, ΔHrxn >0 for this reaction. therefore, this reaction is exothermic.
c) 5.35 mole of CO2 react with 5.35 mole to form 5.35 mole of MgO.
Therefore, change in enthalpy = ΔH = (No. of moles of CO2)(ΔHrxn)
= (5.35 mole)(-117.3 kJ)
= -627.56 kJ
d) 35.5 mole of CO2 react with 35.5 mole to form 35.5 mole of MgO.
Therefore, change in enthalpy = ΔH = (No. of moles of CO2)(ΔHrxn)
= (35.5 mole)(-117.3 kJ)
= -4164.15 kJ
Pb.8. Consider the following balanced thermochenmical equation for the decomposition of the mineral magnesite: MgCOs(s) MgO(s)+CO2(g)...
Consider the following balanced thermochemical equation for the decomposition of the mineral magnesite: MgCO3() – MgO(s) + CO2(g) AH = 117.3 kJ (a) Is heat absorbed or released in the reaction? released absorbed (b) What is AHrn for the reverse reaction? (c) What is AH when 3.10 mol of CO2 reacts with ercess Mgo? kJ (d) What is AH when 33.5 g of CO, reacts with excess 190? kJ
Consider the following balanced thermochemical equation for the decomposition of the mineral magnesite: MgCO3(s) - MgO(s) + CO2(g) AHrxn - 117.3 kJ (a) Is heat absorbed or released in the reaction? released o absorbed (b) What is AHfor the reverse reaction? (@) What is AH when 4.20 mol of CO, reacts with excess MgO? kJ (d) What is AH when 30.0 g of CO, reacts with excess MgO?
Be sure to answer all parts. Consider the following balanced thermochemical equation for the decomposition of the mineral magnesite: MgCO3(s) - MgO(s) + CO2(g) AH - 117.3 kJ (a) Is heat absorbed or released in the reaction? absorbed released (b) What is A n for the reverse reaction? -1173 EJ (c) What is AH when 5.20 mol of CO, reacts with excess Mgo? (a) What is AH when 32.5 g of CO, reacts with exces: Mgo?
Consider the following balanced thermochemical equation for the decomposition of the mineral magnesite: MgCO3 (s) LaTeX: \longrightarrow ⟶ MgO (s) + CO2 (g) LaTeX: \Delta Δ Hrxn = 117.3 kJ If MgO is produced this way, how many grams of MgO can form when 1.000 x 103 kJ of heat is transferred? Show your work.
CHE 120 Pb.3. A 295- aluminum engine part at an initial temperature of 13.00'C absorbs 75.0 kJ of heat. What is the final temperature of the part? (Specific heat capacity of Al = 0.900 Jig K). Pb.4. When 155 mL of water at 26°C is mixed with 75 mL of water at 85°C, what is the final temperature? (Assume no heat lost to the surroundings; density of water = 1.00 g/mL and specific heat capacity of water = 4.184 J/g.K)....
Delete CHE 120 Pb.9.Liquid hydrogen peroxide, an oxidizing agent used in many rocket fuel mixtures, releases oxygen gas on decomposition: AHon=-196.1 kJ -2H2O(I)O2(g) 2H2O2(l) What mass of H2O2 decomposes if 2510 kJ is released?
13. Consider the following equation 2C(s) + 2 H20 (g) CH, (g) + CO2(g) Determine the standard enthalpy change for this reaction from the following standard enthalpies of reaction : (1) C(s) + H2O (g) CO(g) + H, (g) AH° - 131.3 kJ (2) CO(g) + H2O (g) CO2(g) + H2(g) AH° - -41.2 kJ (3) CH, (g) + H,0(g) 3H, (g) + CO(g) AH° - 206.1 kJ A 15.3 B. -116.1 C. 378.2 D. -427.0
13. Consider the following equation 2 C(s) + 2 H2O(g) + CH, (g) + CO2(g) Determine the standard enthalpy change for this reaction from the following standard enthalpies of reaction : (1) C(s) + H2O(g) + CO(g) + H2(g) AH° = 131.3 kJ (2) CO (g) + H2O(g) + CO2(g) + H2(g) AH° = -41.2 kJ (3) CH, (g) + H2O(g) + 3H2(g) + CO (g) AH° = 206.1 kJ A. 15.3 B. -116.1 C. 378.2 D. -427.0
Consider the following reaction. CH,(8) + 30,(8) 200,(g) + 2 H2O(g) Compound C, H.() 0,(g) CO2(g) H2O(g) AH; (kJ/mol) 52.4 0 -393.5 -241.8 What is the AH of the reaction? -687.7 kJ/mol -1323.0 kJ/mol -1218.2 kJ/mol 1323.0 kJ/mol
Time Remaining:03:23 1. Consider the balanced equation for the following reaction: 3Fe2O3(s) + CO(g) + CO2(g) + 2Fe3O4(s) How much excess reactant remains in the reaction if 46.8 grams of Fe2O3 reacts with 22.4 grams of CO? 0.195 moles 0.702 moles 0.800 moles 0.267 moles 0.507 moles Use the slider to rate your confidence on this question 100 Not at all confident Very confident