4) If 46.2 g piece of aluminum is cooled from 84.5 °C to 29.5C, how much...

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Answer 1

Answer #1

☺ using formula, q=mcat Here, q= energy lost m= mass = 46.2g (= specific heat = oogol Ilgic AT = Ty-T, = (29.5-84.5)2 = -55°C

Answer 2

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