6. [Ni(en)]2+ + 6NH3 = [Ni(NH3).]2+ + 3en Show calculation for this and all following K's!...

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Question

6. [Ni(en)]2+ + 6NH3 = [Ni(NH3).]2+ + 3en Show calculation for this and all following Ks! K = 7. [Ni(dien) P* + 6NH = [Ni(NH

Answer 1

Answer #1

Question 6.

'en' is a bidentate ligand, which increases the strength of the metal complex, but NH3 comparatively less stabilizes the metal complex.

i.e. [Ni(en)₃]²⁺ + 2NH₃ <----> [Ni(en)₂(NH₃)₂]²⁺ + en, K₁

[Ni(en)₂(NH₃)₂]²⁺ + 2NH₃ <----> [Ni(en)(NH₃)₄]²⁺ + en, K₂

[Ni(en)₂(NH₃)₄]²⁺ + 2NH₃ <----> [Ni(NH₃)₆]²⁺ + en, K₃

Now, the overall equilibrium constant for the formation of [Ni(NH₃)₆]²⁺ from [Ni(en)₃]²⁺ can be calculated as follows.

K = K₁ * K₂ * K₃

Answer 2

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