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Question 1 1 pts A parallel -plate capacitor of capacitance C with distance d between plates is fully charged from a battery of voltage V and then disconnected. The plates of capacitor are slowly pulled to the half of initial distance (d/2). Voltage of capacitor is now: 2V 4V

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Answer #1

Since battery is disconnected, and after that only plates are bring closer to half of original distance, electric potential difference reduces to half

Answer: V/2

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