Ans:
6)
Binomial distribution with n=10 and p=0.05
P(x=k)=10Ck*0.05k*(1-0.05)10-k
x | p(x) |
0 | 0.5987 |
1 | 0.3151 |
2 | 0.0746 |
3 | 0.0105 |
4 | 0.0010 |
5 | 0.0001 |
6 | 0.0000 |
7 | 0.0000 |
8 | 0.0000 |
9 | 0.0000 |
10 | 0.0000 |
a)P(x=0)=(1-0.05)10=0.5987
b)P(x=1)=10C1*0.051*0.959=0.3151
c)P(x<=2)=P(x=0)+P(x=1)+P(x=2)
=0.5987+0.3151+0.0746=0.9885
d)
P(x>=2)=1-P(x=0)-P(x=1)
=1-0.5987-0.3151=0.0861
Problem 6. (Binomial distribution) A company produces light bulbs. Each bulb is checked before it leaves...
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