Question

) The ‘carrier' of the weak interaction are the massive weak osons W and the z (mzc2 93 GeV, mwc2 82 GeV) which c implies that the weak interactions have a short range. Prove that

Answer 1

We know that the range is given by

R = speed x time

$R = \frac{\not{h}c}{Mc^{2}}$

$R = \frac{197 }{Mc^{2}}$ this is in Mev-fm

if i put the above values of W and Z then

$R z= \frac{197 \times 10^{6}}{93 \times 10^{9}} = 2.12 fm$

$R w= \frac{197 \times 10^{6}}{82 \times 10^{9}} = 2.4 fm$

This is very short as compare to other forces as they have infinite range.

So weak interaction have short range