Question

Diana M. Bailey conducted a study to examine the causes by which occupational therapists leave the field of occupational therapy (A-18). The sample is made up of women certified occupational therapists who left the profession temporarily or permanently. Of the 696 individuals who responded to a survey to collect data, 63 percent decided to leave their jobs to dedicate themselves to having and caring for their own children. Based on these data, is it possible to conclude that, in general, more than 60 percent of the individuals in the sample population decided to leave their jobs to dedicate themselves to having and taking care of their own children? Let gamma = .05. What is the population sampled? What assumptions are necessary for the procedure to be valid?

Answer 1

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1.

Here' the answer to the question. Please don't hesitate to give a "thumbs up" in case you're satisfied with the answer

Lets see, we have been provided with the following info:

n = 696
p = .60
p^ = .63

alpha = .05

Lets calculate the test statistic,
t = (p^-p)/sqrt(p*p'/n)
= (.63-.60)/sqrt(.6*.4/696)
= 1.62

So, we have been asked to get, P(Z>1.62) which by the Z table is 0.053

Since, this value is more than gamma(critical value) of .05, we conclude that we fail to reject Ho
and say that the is it NOT possible to conclude that, in general, more than 60 percent of the individuals in the sample population decided to leave their jobs to dedicate themselves to having and taking care of their own children

2. The population sampled is : Occupational therapists leave the field of occupational therapy

3. The assumptions of this one-sample t-test are:

1. The data are continuous (not discrete).

2. The data follow the normal probability distribution.

3. The sample is a simple random sample from its population. Each individual in the population has an equal probability of being selected in the sample.