Question

the specific heat of ethanol is 2.46 j/gc. when 2555 j of heat are added to 32.8 g ethanol, a final temperature of 77.5 c is reached. what was the initial temperature of ethanol

Answer 1

q=mcΔt,

where q is heat in Joules, m is mass in g, c is specific heat capacity in J/g⁰C, and Δt is change in temperature: Δt=(T_final−T_initial)

q=2555J

m=32.8 g

c=2.46 J/g⋅C∘

T_initial=?

T_final=77.5 ⁰C

Δt=77.5-T_initial

2555J =32.8g*2.46J/g⋅C∘*(77.5-T_initial)

77.5-T_initial=2555J/(32.8g*2.46J/g⋅C∘) =31.6⁰C

T_initial=77.5-31.6=45.9⁰C

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