The thermal decomposition of NO2: 2
NO2(g) → 2 NO(g) +
O2(g) takes place in two steps:
(1)
2 NO2(g) → NO3(g) +
NO(g) (slow) (2)
NO3 → NO(g) +
O2(g) (fast)
Which of the following
statements is true?
a. Rate = k
[NO2] b. The reaction is
second order in
NO2. c.
The reaction is first order in O2.
d. Increasing [NO2] has no effect on reaction
rate. e. All the above.
The thermal decomposition of NO2: 2 NO2(g) → 2 NO(g) + O2(g) takes place in two steps: (1)...
For the reaction 2 NO (g) + O2 (g) → 2 NO2 (g) it is found that the rate doubles when the O2 concentration is doubled, but the rate increases by a factor of 4 when the NO concentration is doubled. Which of the following mechanisms is/are consistent with this? 1. (i) NO + O2 ⇋ NO3 (fast) (ii) NO + NO3 → 2 NO2 (slow) 2. (i) 2 NO → N2O2 (slow) (ii) O2 + N2O2 → N2O4 (fast)...
1a. The reaction of NO and O2 produces NO2. 2 NO(g) + O2(g) → 2 NO2(g) The reaction is second order with respect to NO(g) and first order with respect to O2(g). At a given temperature, the rate constant, k, equals 4.6 x 102 M–2 s–1. When the initial concentrations of NO and O2 are 0.02 M and 0.015 M, respectively, the rate of the reaction is ___ M/s. 1b. The rate constant of a first-order decomposition reaction is 0.014...
A proposed mechanism for a reaction is as follows: NO2(g) + NO2(g) + N204(8) Fast/Equilibrium Step N2048) -> NO(g) + NO3(g) Slow NO3(g) NO) + O2(g) Fast The target rate law is rate = k (NO2)2 The target reaction is 2NO2(e) 2NON + O2) A. Write the rate law expected for this mechanism: B. What is the rate-determining step? C. What is the overall balanced equation for this mechanism? D. If there is/are a reactive intermediate(s), which is/are they? E....
The decomposition of NO2 at high temperature NO2(g) → NO(g) + 1/2 O2(g) is a second order process with a rate constant of 3.40 L/mol•min. If an experiment is performed where the initial concentration of NO2 is 0.400 M, what is the concentration of NO2after 2.96 min? [NO2] = M
The decomposition of nitrogen dioxide occurs according to the equation below: NO2 (g)------>NO( g)+1/2 O2 (g) The reaction is second order with respect to NO2. The specific rate constant for this reaction is 3.04M-1min-1. How long does it take for the concentration of NO2 to decrease from 2.00M to 1.25M?
The reaction of NO and O2 produces NO2. 2 NO(g) + O2(g) → 2 NO2(g) The reaction is second-order with respect to NO(g) and first-order with respect to O2(g). At a given temperature, the rate constant, k, equals 4.7E+2 M–2s–1. What is the rate of reaction when the initial concentrations of NO and O2 are 1.95E-2 M and 1.40E-2 M, respectively? 5.32E-6 M/s 2.50E-3 M/s 1.80E-3 M/s 0.128 M/s -2.50E-3 M/s
The reaction 2 NO2 --> 2 N2 + O2 follows the mechanism: Step 1: NO2 --NO NO3 NO2 SLOW + + Step 2: NO3 CO FAST NO2 CO2 -> + What is the intermediate in the reaction? none of these NO2 ONO3 OOOO
The nitrogen-monoxide-catalyzed decomposition of dinitrogen monoxide is thought to proceed by a two-step mechanism: NO(g) + N2O(g) --> N2(g) + NO2(g) (slow) 2 NO2(g) --> 2 NO(g) + O2(g) (a) If the first step of this mechanism is rate-determining (slow), choose the correct rate law for the overall process. Rate = k [N2O]2 Rate = k [NO] [NO2] Rate = k [N2O]2 [N2O] Rate = k [NO2] [N2O] Rate = k [N2O] [N2O] Rate = k [NO] [N2O] (b) Choose...
from rxn mechanism 03+ no2 ->no3 +o2 (slow) no3+no2->n2o5 (fast) rate=k [o3]1 [no2]1 so here, I see that order is 1 for [o3] and [no2] because o3 + no2 has 1 coefficient in front. but my question is I learned that the order of reaction is not equal to the coefficient of species. !! so why coefficient is determined when writing rate of reaction here? this does not make sense to me.
10. Consider the reaction that takes place via the mechanism below; STEPI: NO2(g) + CO(g) → NO(g) + CO2(e) (fast) STEP II: NO(8) + Cl2(e) → NOCl2(g) (slow) Determine; (a) The reaction intermediate(s) (2 points) (b) The rate determining step (2 points)