Homework Answers
Mass of Mo in given oxide = (95.96×2/239.92)×14.11g = 11.287g
Mass of oxygen in new oxide = 15.05g-11.287g = 3.763g
Number of.moles of Mo = 11.287g/95.96g/mol = 0.1176mol
Number of moles of Oxygen = 3.763g/16g/mol = 0.2352mol
Relative ratio of moles of Mo : O = 1: 2
Empirical formula : MoO2. (Answer)
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A 25.121 mg sample of a chemical known to contain only carbon, hydrogen, sulfur, and oxygen...
A 25.121 mg sample of a chemical known to contain only carbon, hydrogen, sulfur, and oxygen is put into a combustion analysis apparatus, yielding 44.751 mg of carbon dioxide and 18.319 mg of water. In another experiment, 29.077 mg of the compound is reacted with excess oxygen to produce 12.57 mg of sulfur dioxide. Add subscripts to the formula provided to correctly identify the empirical formula of this compound. Do not change the order of the elements. empirical formula: CHSO
A 24.117 mg sample of a chemical known to contain only carbon, hydrogen, sulfur, and oxygen...
A 24.117 mg sample of a chemical known to contain only carbon, hydrogen, sulfur, and oxygen is put into a combustion analysis apparatus, yielding 42.963 mg of carbon dioxide and 17.587 mg of water. In another experiment, 32.443 mg of the compound is reacted with excess oxygen to produce 14.02 mg of sulfur dioxide. Add subscripts to the formula provided to correctly identify the empirical formula of this compound. Do not change the order of the elements. empirical formula: CHSO
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A 25.121 mg sample of a chemical known to
contain only carbon, hydrogen, sulfur, and oxygen is put into a
combustion analysis apparatus, yielding 44.751 mg of carbon dioxide
and 18.319 mg of water. In another experiment, 30.199 mg of the
compound is reacted with excess oxygen to produce 13.05 mg of
sulfur dioxide. Add subscripts to the formula provided to correctly
identify the empirical formula of this compound. Do not change the
order of the elements.
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A 24.117 mg sample of a chemical known to contain only carbon, hydrogen, sulfur, and oxygen is put into a combustion analysis apparatus, yielding 42.963 mg of carbon dioxide and 17.587 mg of water. In another experiment, 32.443 mg of the compound is reacted with excess oxygen to produce 14.02 mg of sulfur dioxide. Add subscripts to the formula provided to correctly identify the empirical formula of this compound. Do not change the order of the elements. empirical formula: C,H,...
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A 27.129 mg sample of a chemical known to contain only carbon, hydrogen, sulfur, and oxygen is put into a combustion analysis apparatus, yielding 48.328 mg of carbon dioxide and 19.783 mg of water. In another experiment, 29.077 mg of the compound is reacted with excess oxygen to produce 12.57 mg of sulfur dioxide. Add subscripts to the formula provided to correctly identify the empirical formula of this compound. Do not change the order of the elements empirical formula: CHSO
A 1.000-g sample of lead shot reacted with oxygen to give 1.077 g of product. Fill-in the blanks, to finally determine the empirical formula of the lead oxide. Refer to Example Exercise 1 Record your numbers to 3 significant figures. Do not use exponential notation or subscripts in your answers. a) The mass of oxygen used in the reaction is b) The number of moles of lead is moles and the number of moles of oxygen is moles. c) Using...
A 30.141 mg sample of a chemical known to contain only carbon, hydrogen, sulfur, and oxygen is put into a combustion analysis apparatus, yielding 53.694 mg of carbon dioxide and 21.980 mg of water. In another experiment, 30.199 mg of the compound is reacted with excess oxygen to produce 13.05 mg of sulfur dioxide. Add subscripts to the formula provided to correctly identify the empirical formula of this compound. Do not change the order of the elements empirical formula: CHSO
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